Answer:
The answer to your question is given below.
Explanation:
Mechanical advantage (MA) = Load (L)/Effort (E)
MA = L/E
Velocity ratio (VR) = Distance moved by load (l) / Distance moved by effort (e)
VR = l/e
Efficiency = work done by machine (Wd) /work put into the machine (Wp) x 100
Efficiency = Wd/Wp x100
Recall:
Work = Force x distance
Therefore,
Work done by machine (wd) = load (L) x distance (l)
Wd = L x l
Work put into the machine (Wp) = effort (E) x distance (e)
Wp = E x e
Note: the load and effort are measured in Newton (N), while the distance is measured in metre (m)
Efficiency = Wd/Wp x100
Efficiency = (L x l) / (E x e) x 100
Rearrange
Efficiency = L/E ÷ l/e x 100
But:
MA = L/E
VR = l/e
Therefore,
Efficiency = L/E ÷ l/e x 100
Efficiency = MA ÷ VR x 100
Efficiency = MA / VR x 100
<span>Here I think you have to find the velocity in x and y components where x is east and y is north
So as air speed indicator shows the negative speed in y component and adding it in
air speed while multiplying with the direction component we will get the velocity as velocity is a vector quantity so direction is also required
v=-28 m/s y + 18 m/s (- x/sqrt(2) - y/sqrt(2))
solving
v= -12.7 m/s x-40.7 m/s y
if magnitude of velocity or speed is required then
speed= sqrt(12.7^2 + 40.7^2)
speed= 42.63 m/s
if angle is asked
angle = arctan (40.7/12.7)
angle = 72.67 degrees south of west</span>
Materials required for the experiment of limiting force borne by string:-
- String balance
- weights
- light strings
- weight hanger
- pan for spring balance
- Sand
Steps of procedure for for the experiment of limiting force borne by string:-
- First we have to tie a light string to the fixed support and then tie the other end with the weight hanger consists of weight.
- Add additional weight to the hanger again and again. And continue the same until the string is broken.
- Note down the weight (x) where the string is broken.
- Suspend spring balance to a support.
- Tie the light string at the end of the balance and at the other end suspend the pan for spring balance.
- Now place the weights (x-100 grams) in pan.
- Observe the reading in the spring balance.
- Add a small amount of sand in the pan by observing the readings.
- same is to be done till the string is broken.
Learn more about limiting force here:- brainly.com/question/11371672
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If one of the answers are the coin will float that one would be correct.
Answer:
15.6m/s
Explanation:
V1=
because the derivate of the position is the velocity
V1=12t+3
V2=20+
-8t because the integral of the acceleration is the velocity
V2=
V1=V2 to see when the velocities of particles match
12t+3=20-4t^2
4t^2+12t-17=0 we resolve this with 
and we take the positif root
t=1.05 sec
if we evaluate the velocity (V1 or V2) the result is 15.6m/s
