Answer:
Explanation:
The definition of angular velocity is as follows:
where 
is the angular velocity, and 
is the frequency.
Frequency can also be represented as:
where 
is the period, (the time it takes to conclude a cycle)
with this, the angular velocity is:
The period T of rotation around the sun 365 days, thus, the angular velocity:
if we want the angular velocity in rad/second, we need to convert the 365 days to seconds:
Firt conveting to hous
then to minutes
and finally to seconds
thus, angular velocity in rad/second is:
The concept used to solve this problem is that given in the kinematic equations of motion. From theory we know that the change in velocities of a body is equivalent to twice the distance traveled by acceleration, in other words:
Where,
Final and initial velocity
a = Acceleration
x = Displacement
For the given case, the displacement is equivalent to the height (x = h) and the acceleration is the same gravitational acceleration (a = g). In turn we do not have initial speed therefore
Our values are given as
Replacing we have that,
Therefore the speed with which the liquid sulfur left the volcano is 529.15m/s
Answer:
11. Depression
Explanation:
11. Many people face depression and don't know how to fix or deal with the problem in a healthy way.
12. It can be controlled by the stuff you eat for example if you don't eat lunch you may be hungry which is bad plus the depression.
B will be your answer hope this helped
Answer: 6.36
Explanation:
Given
Radius of grindstone, r = 4 m
Initial angular speed of grindstone, w(i) = 8 rad/s
Final angular speed of the grindstone, w(f) = 12 rad/s
Time used, t = 4 s
Angular acceleration of the grinder,
α = Δw / t
α = w(f) - w(i) / t
α = (12 - 8) / 4
α = 4/4 = 1 rad/s²
Number of complete revolution in 4s =
Δθ = w(i).t + 1/2.α.t²
Δθ = 8 * 4 + 1/2 * 1 * 4²
Δθ = 32 + 1/2 * 16
Δθ = 32 + 8
Δθ = 40 rad/s
40 rad/s = 40/2π rpm = 6.36 rpm
Therefore, the grindstone does 6.36 revolutions during the 4 s interval
