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Nadya [2.5K]
3 years ago
15

Explain why an atom can only emit specific wavelengths of light and not every possible wavelength

Chemistry
1 answer:
ella [17]3 years ago
5 0

Answer:

<em>The electrons in an atom can only occupy certain allowed energy levels to a lower one</em>, the excess energy is emitted as a photon of light, with its wavelength dependent on the change in electron energy. This is why an atom can only emit specific wavelengths of light and not every possible wavelength.

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Balance the equation by inserting coefficients as needed. equation: ZnS + HBr -&gt; ZnBr_{2} + H_{2}S ZnS + HBr ⟶ ZnBr 2 + H 2 S
yawa3891 [41]

Answer : The balanced chemical reaction will be,

ZnS+2HBr\rightarrow ZnBr_2+H_2S

Explanation :

Balanced chemical reaction : It is defined as the reaction in which the number of atoms of individual elements present on reactant side must be equal to the product side.

If the amount of atoms of each type on the left and right sides of a reaction differs then to balance the equation by adding coefficient in the front of the elements or molecule or compound in the chemical equation.

The coefficient tell us about that how many molecules or atoms present in the chemical equation.

The given chemical reaction is,

ZnS+HBr\rightarrow ZnBr_2+H_2S

This reaction is an unbalanced chemical reaction because in this reaction number of hydrogen bromine atoms are not balanced.

In order to balance the chemical equation, the coefficient '2' put before the HBr and we get the balanced chemical equation.

The balanced chemical reaction will be,

ZnS+2HBr\rightarrow ZnBr_2+H_2S

8 0
3 years ago
The smallest unit which maintains the physical properties of a compound is a(n _____. atom element molecule alloythe smallest un
LuckyWell [14K]
The answer that would best complete the given statement above is the term ATOM. <span>The smallest unit which maintains the physical properties of a compound is an ATOM. But for a compound, it would be molecule. Hope this answers your question.</span>
5 0
4 years ago
Hypothesis: If a material undergoes a
zepelin [54]

Answer:

I hate to not answer and have you repost this if you could repost it with the choices by clicking the arrow I can figure it out a lot faster and I'll copy and paste to show you that it's right

Explanation:

I'm good with history biology sum math so if you want to do what I asked and reposted I can give you the answers and I will show that they are correct I won't just guess like some people do just to get points cuz I don't care about points I just get on here to help people

8 0
3 years ago
Read 2 more answers
(part 1 of 3) Copper reacts with silver nitrate through a single replacement. If 1.29 g of silver are produced from the reaction
ale4655 [162]

Answer:

See explanation.

Explanation:

Hello there!

In this case, according to the described chemical reaction, we first write the corresponding equation to obtain:

Cu+2AgNO_3\rightarrow 2Ag+Cu(NO_3)_2

Thus, we proceed as follows:

Part 1 of 3: here, since the molar mass of silver and copper (II) nitrate are 107.87 and 187.55 g/mol respectively, and the mole ratio of the former to the latter is 2:1, we can set up the following stoichiometric expression:

m_{Cu(NO_3)_2}=1.29gAg*\frac{1molAg}{107.87gAg}*\frac{1molCu(NO_3)_2}{2molAg}*\frac{187.55gCu(NO_3)_2}{1molCu(NO_3)_2}   \\\\m_{Cu(NO_3)_2}=1.12gCu(NO_3)_2

Part 2 of 3: here, the molar mass of copper is 63.55 g/mol and the mole ratio of silver to copper is 2:1, the mass of the former that was used to start the reaction was:

m_{Cu}=1.29gAg*\frac{1molAg}{107.87gAg}*\frac{1molCu}{2molAg}*\frac{63.55gCu)_2}{1molCu}   \\\\m_{Cu}=0.380gCu

Part 3 of 3: here, the molar mass of silver nitrate is 169.87 g/mol and their mole ratio 2:2, thus, the mass of initial silver nitrate is:

m_{AgNO_3}=1.29gAg*\frac{1molAg}{107.87gAg}*\frac{2molAgNO_3}{2molAg}*\frac{169.87gAgNO_3}{1molAgNO_3}   \\\\m_{AgNO_3}=2.03gAgNO_3

Best regards!

5 0
3 years ago
Sắp xếp các hợp chất: HF, HI, HBr, HCl theo chiều giảm dần tính axit.
mixer [17]
I don’t know what to answer
6 0
2 years ago
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