Ask question

Ask question

All categories

3 years ago

5

A small flashlight bulb provides a resistance of 3 Ω to the 300 mA current that runs through it. Determine the voltage of the ba

ttery in the flashlight.

1 answer:

Contact [7]3 years ago

3 0

V=IR

V= 0.3 x 3

V= 0.9V

You might be interested in

The tangential acceleration of a cart moving at a constant speed in a horizontal circle is:

qaws [65]

Answer:

$a=0$ ∵ $\alpha=0\ rad.s^{-1}$

Explanation:

The tangential acceleration of a cart moving at a constant speed in a circle is:

The angular velocity is constant when the circular speed is constant.

We know that the (instantaneous) tangential velocity of such object is given by:

$v=r.\omega$

Now for angular acceleration we have a constant angular speed:

$\alpha=0\ rad.s^{-1}$

And angular acceleration is related to tangential acceleration as:

$a=r.\alpha$

$\Rightarrow a=0$

7 0

3 years ago

Kind of mixture that has the same mixture throughout

Ainat [17]

It's a homogeneous mixture
<span />

8 0

3 years ago

Read 2 more answers

Some superconductors are capable of carrying a very large quantity of current. If the measured current is 1.00 ´ 105 A, how many

Zielflug [23.3K]

Answer:

The $6.25 \times 10^{23}$ electrons are moving through the superconductor per second.

Explanation:

Given :

Current $I = 1 \times 10^{5}$ A

Charge of electron $e = 1.6 \times 10^{-19}$ C

Time $t = 1$ sec

From the formula of current,

Current is the number of charges flowing per unit time.

$I = \frac{ne}{t}$

Where $n =$ number of charges means in our case number of electrons

$n = \frac{It}{e}$

$n = \frac{1 \times 10^{5} }{1.6 \times 10^{-19} }$

$n = 6.25 \times 10^{23}$

Therefore, $6.25 \times 10^{23}$ electrons are moving through the superconductor per second.

5 0

3 years ago

stellarik [79]

Answer: $0.69\°$

Explanation:

The angular diameter $\delta$ of a spherical object is given by the following formula:

$\delta=2 sin^{-1}(\frac{d}{2D})$

Where:

$d=16 m$ is the actual diameter

$D=1338 m$ is the distance to the spherical object

Hence:

$\delta=2 sin^{-1}(\frac{16 m}{2(1338 m)})$

$\delta=0.685\° \approx 0.69\°$ This is the angular diameter

3 0

3 years ago

There are several events listed below some of the events are related to tectonic plates activity mark each that is associated wi

iVinArrow [24]

A because an earthquake is shaking of tectonic plates

5 0

3 years ago