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suter [353]
3 years ago
11

PLZ HELP !!!! WILL MARK BRAINLIEST, THIS IS DUE IN 15 MINUTIES !!!ANYONE PLEASEPLZ HELP !!!! WILL MARK BRAINLIEST, THIS IS DUE I

N 15 MINUTIES !!!ANYONE PLEASEPLZ HELP !!!! WILL MARK BRAINLIEST, THIS IS DUE IN 15 MINUTIES !!!ANYONE PLEASE

Mathematics
2 answers:
dlinn [17]3 years ago
7 0

Answer:

C!!!!!!!!!!!!!!!!!!!!!

Step-by-step explanation:

Have a good day UvU

Allisa [31]3 years ago
6 0

Answer and Step-by-step explanation:(MAKE ME BRAINLIEST)

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Lian is paid for SR 75 per hour. Using p for her pay and h for the hours of work, which function rule represents
Andru [333]

Answer:

The function p = 75h represents  this situation.

Step-by-step explanation:

We know the equation of linear equation in the slope-intercept form is

y = mx+b

where

m = rate of change = slope

b = y-intercept

  • Let 'h' be the number of hours
  • Let 'p' be the pay

Given that Lian is paid SR 75 per hour.

so the rate of change of slope = m = 75

As there is no initial condition, so b = 0

as

y = mx+b

Now, mapping the information data into the slope-intercept form

  • p = y
  • m = 75
  • h = x
  • b = 0

Thus, the equation becomes

p = 75h

Therefore, the function p = 75h represents  this situation.

VERIFICATION:

Given the equation

p = 75h

for h = 1

p = 75(1)

p = 75

Thus, Liam is paid SR 75 per hour.

4 0
2 years ago
Roy Gross is considering an investment that pays 7.6 percent, compounded annually. How much will he have to invest today so that
Debora [2.8K]

Answer: he should invest $16129 today.

Step-by-step explanation:

Let $P represent the initial amount that should be invested today. It means that principal,

P = $P

It would be compounded annually. This means that it would be compounded once in a year. So

n = 1

The rate at which the principal would be compounded is 7.6%. So

r = 7.6/100 = 0.076

The duration of the investment would be 6 years. So

t = 6

The formula for compound interest is

A = P(1+r/n)^nt

A = total amount in the account at the end of t years.

A = 25000

Therefore

25000 = P(1+0.076/1)^1×6

25000 = P(1.076)^6

25000 = 1.55P

P = 25000/1.55

P = $16129

4 0
3 years ago
Which statement is the Law of Detachment? (1 point)
creativ13 [48]
The law of detachment<span> allows you to "detach" the hypothesis from the conclusion. If we know both that </span>p<span> and </span>p<span> → </span>q<span> to be true, then we may conclude that </span>q<span> is true.

So the answers is the fourth one: I</span>f p <span>→</span><span> q is a true statement and p is true, then q is true.</span>
5 0
3 years ago
in exercises 15-20 find the vector component of u along a and the vecomponent of u orthogonal to a u=(2,1,1,2) a=(4,-4,2,-2)
Nimfa-mama [501]

Answer:

The component of \vec u orthogonal to \vec a is \vec u_{\perp\,\vec a} = \left(\frac{9}{5},\frac{6}{5},\frac{9}{10},\frac{21}{10}\right).

Step-by-step explanation:

Let \vec u and \vec a, from Linear Algebra we get that component of \vec u parallel to \vec a by using this formula:

\vec u_{\parallel \,\vec a} = \frac{\vec u \bullet\vec a}{\|\vec a\|^{2}} \cdot \vec a (Eq. 1)

Where \|\vec a\| is the norm of \vec a, which is equal to \|\vec a\| = \sqrt{\vec a\bullet \vec a}. (Eq. 2)

If we know that \vec u =(2,1,1,2) and \vec a=(4,-4,2,-2), then we get that vector component of \vec u parallel to \vec a is:

\vec u_{\parallel\,\vec a} = \left[\frac{(2)\cdot (4)+(1)\cdot (-4)+(1)\cdot (2)+(2)\cdot (-2)}{4^{2}+(-4)^{2}+2^{2}+(-2)^{2}} \right]\cdot (4,-4,2,-2)

\vec u_{\parallel\,\vec a} =\frac{1}{20}\cdot (4,-4,2,-2)

\vec u_{\parallel\,\vec a} =\left(\frac{1}{5},-\frac{1}{5},\frac{1}{10},-\frac{1}{10} \right)

Lastly, we find the vector component of \vec u orthogonal to \vec a by applying this vector sum identity:

\vec  u_{\perp\,\vec a} = \vec u - \vec u_{\parallel\,\vec a} (Eq. 3)

If we get that \vec u =(2,1,1,2) and \vec u_{\parallel\,\vec a} =\left(\frac{1}{5},-\frac{1}{5},\frac{1}{10},-\frac{1}{10} \right), the vector component of \vec u is:

\vec u_{\perp\,\vec a} = (2,1,1,2)-\left(\frac{1}{5},-\frac{1}{5},\frac{1}{10},-\frac{1}{10}    \right)

\vec u_{\perp\,\vec a} = \left(\frac{9}{5},\frac{6}{5},\frac{9}{10},\frac{21}{10}\right)

The component of \vec u orthogonal to \vec a is \vec u_{\perp\,\vec a} = \left(\frac{9}{5},\frac{6}{5},\frac{9}{10},\frac{21}{10}\right).

4 0
3 years ago
X=3y + 1<br> 2x + 4y =12
Alika [10]

Answer:

the solution is (4, 1).

Step-by-step explanation:

The goal here is to "solve this system of linear equations."  You need to share that along with the equations.

We can begin the solution by substituting 3y + 1 for x in the second equation:

2(3y + 1) + 4y = 12

Performing the multiplication, we get 6y + 2 + 4y = 12, or 10y = 10.

Then y must be 1.

Substituting 1 for y in the first equation, we get x = 3(1) + 1 = 4

Thus, the solution is (4, 1).

4 0
3 years ago
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