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3 years ago

7

Show the expanded notation for 3c + 6c.

1 answer:

Kruka [31]3 years ago

8 0

Answer:

C ( 3 + 6)

Expanded.

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Tobin is solving the equation 3 (x minus 1.25) = 11.25. His work is shown below.

Bezzdna [24]

Answer:

tobin should have divided by three

Step-by-step explanation:

6 0

2 years ago

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Heather is going to graph y = -3x2 + 3. How is the parent graph transformed?

Yuki888 [10]

Any x² graph is a parabola. The negative in front is going to flip the parabola upside down to look like a camel hump. The 3 is going to make the graph narrower. The three at the end makes the y intercept 3. So the top of the graph will be shifted up to (0,3).
The answer would be A I believe

3 0

3 years ago

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Plsss hElpp!!!!! TY!!

kari74 [83]

Given:

A circle with diameter 9 cm.

To find:

The area of the circle.

Solution:

The area of a circle is:

$A=\pi r^2$ ...(i)

Where r is the radius.

We know that, the diameter of a circle is twice than its radius.

The diameter of the given circle is 9 cm.

$r=\dfrac{9}{2}$

$r=4.5$

Substituting $r=4.5, \pi =3.14$ in (i), we get

$A=(3.14)(4.5)^2$

$A=(3.14)(20.25)$

$A=63.585$

$A\approx 63.6$

Therefore, the area of the given circle is 63.6.

4 0

3 years ago

Help me out please?<br>chapter : exponents and powers

belka [17]

Answer:

$\frac{125}{27}$

Step-by-step explanation:

$\frac{2^{-4} \times 15^{-3} \times 625}{5^2 \times 10^{-4}}$

Lets expand all the composite numbers into prime numbers.

$=> \frac{2^{-4} \times (3^{-3} \times 5^{-3}) \times 5^4}{5^2 \times (2^{-4} \times 5^{-4})}$

Lets cancel $2^{-4}$ from numerator and denominator.

$=> \frac{3^{-3} \times 5^{-3} \times 5^4}{5^2 \times 5^{-4}}$

Using laws of exponents , lets solve this.

$=> \frac{3^{-3} \times 5^{(-3 + 4)}}{5^{( 2 - 4)}}$

$=> \frac{3^{-3} \times 5^{1}}{5^{-2}}$

$=> 3^{-3} \times 5^{[1 - (-2)]}$

$=> 3^{-3} \times 5^{3}$

$=> \frac{5^3}{3^3} = \frac{125}{27}$

4 0

3 years ago

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Simplify: 5x + 4 + 9x

Klio2033 [76]

The correct answer is; 14x +4

8 0

3 years ago

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