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Romashka [77]
2 years ago
6

What is the domain and path in this URL? www.example.com/homepage.html​

Computers and Technology
1 answer:
Alex17521 [72]2 years ago
4 0

Answer:

the domain is example.com. the path is /homepage

Explanation:

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Three materials needed to stream video video content
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Oh yeah yeah I don’t know ‍♂️ is
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The set of three integer values for the lengths of the sides of a right triangle is called a Pythagorean triple. These three sid
Sloan [31]

Answer:

In Python:

def  Pythagorean_triple(hyp,side1,side2):

   if hyp**2 == side1**2 + side2*2:

       return True

   else:

       return False

               

print("Hypotenuse\tSide 1\t Side 2\t Return Value")

for i in range(1,501):

   for j in range(1,501):

       for k in range(1,501):

           print(str(i)+"\t"+str(j)+"\t"+str(k)+"\t"+str(Pythagorean_triple(i,j,k)))

Explanation:

This defines the function

def  Pythagorean_triple(hyp,side1,side2):

This checks for pythagorean triple

   if hyp**2 == side1**2 + side2*2:

Returns True, if true

       return True

   else:

Returns False, if otherwise

       return False

               

The main method begins

This prints the header

print("Hypotenuse\tSide 1\t Side 2\t Return Value")

The following is a triple-nested loop [Each of the loop is from 1 to 500]

for i in range(1,501): -->The hypotenuse

   for j in range(1,501): -->Side 1

       for k in range(1,501):-->Side 2

This calls the function and prints the required output i.e. the sides of the triangle and True or False

           print(str(i)+"\t"+str(j)+"\t"+str(k)+"\t"+str(Pythagorean_triple(i,j,k)))

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3 years ago
Ok i dont wanna get bannddddddd so i have to ask a qustion<br> 2 plus 2
Evgesh-ka [11]

Answer:

22 or 4

Explanation:

:)

3 0
2 years ago
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The value of the mathematical constant e can be expressed as an infinite series: e=1+1/1!+1/2!+1/3!+... Write a program that app
LUCKY_DIMON [66]

Answer:

// here is code in c++ to find the approx value of "e".

#include <bits/stdc++.h>

using namespace std;

// function to find factorial of a number

double fact(int n){

double f =1.0;

// if n=0 then return 1

if(n==0)

return 1;

for(int a=1;a<=n;++a)

       f = f *a;

// return the factorial of number

return f;

}

// driver function

int main()

{

// variable

int n;

double sum=0;

cout<<"enter n:";

// read the value of n

cin>>n;

// Calculate the sum of the series

  for (int x = 0; x <= n; x++)

  {

     sum += 1.0/fact(x);

  }

  // print the approx value of "e"

    cout<<"Approx Value of e is: "<<sum<<endl;

return 0;

}

Explanation:

Read the value of "n" from user. Declare and initialize variable "sum" to store the sum of series.Create a function to Calculate the factorial of a given number. Calculate the sum of all the term of the series 1+1/1!+1/2!.....+1/n!.This will be the approx value of "e".

Output:

enter n:12

Approx Value of e is: 2.71828

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3 years ago
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