Question

Calculate the molarity of an HCl solution if 25.0 mL of the solution is neutralized by 15.5 mL of 0.800 M NaOH. Below is the unbalanced equation: ______ HCl + _____ NaOH →____ H2O + _____ NaCl

Answer 1

Answer:

.496 M .

Explanation:

15.5 mL of .8 M NaOH will contain .0155 x .8 moles of  NaOH

moles of  NaOH = .0124 moles

For neutralization,  moles contained by 25 mL of HCl  = .0124

Hence molarity of HCl = .0124 / .025

= .496 M .