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ELEN [110]
3 years ago
11

(4) NH3+02- NO+H2Obalance the equation​

Chemistry
1 answer:
neonofarm [45]3 years ago
8 0

Answer:

4NH₃ + 5O₂ —> 4NO + 6H₂O

Explanation:

NH₃ + O₂ —> NO + H₂O

The above equation can be balance as follow:

NH₃ + O₂ —> NO + H₂O

There 3 atoms of H on the left side and 2 atoms on the right side. It can be balance by 4 in front of NH₃ and 6 in front of H₂O as shown below:

4NH₃ + O₂ —> NO + 6H₂O

There are 4 atoms of N on the left side and 1 atom on the right side. It can be balance by putting 4 in front of NO as shown below:

4NH₃ + O₂ —> 4NO + 6H₂O

There are 2 atoms of O on the left side and a total of 10 atoms on the right side. It can be balance by putting 5 in front of O₂ as shown below:

4NH₃ + 5O₂ —> 4NO + 6H₂O

Thus, the equation is balanced.

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Calculate the change in temperature that occurs when 3.50 x 10^-2kg of copper heated by 635 J of energy. Ccu = 0.385 j/gxC
vovikov84 [41]

Answer:

The change in T° is 47.1 °C

Explanation:

Calorimetry formula to solve this:

Q = m . C . ΔT

We replace the data gien:

635 J = 3.50×10⁻² kg . 0.385 J/g°C . ΔT

In units of C, we have g and the mass (m) is in kg. So let's convert it from kg to g → 3.50×10⁻² kg . 1000 g / 1kg = 35 g. Now we can determine the ΔT:

635 J = 35 g . 0.385 J/g°C . ΔT

635 J / 35 g . 0.385 J/g°C = ΔT

47.1°C = ΔT

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