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3 years ago

What is the frequency of motion of a 0.50 m long pendulum?

2 answers:

4 0

1. Write down the formula for "frequency of a pendulum" from your textbook.

f = (1/2pi) * sqrt(g/L)

2. Plug in g and L.

Hope this helps!

IgorC [24]3 years ago

3 0

Complicated 2-step process.

1. Write down the formula for "frequency of a pendulum" from your textbook. 

f = (1/2pi) * sqrt(g/L) 

2. Plug in g and L.

I hope this can help!

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PLEASE ASAP HELP, ILL GIVE WHATEVER POINTS I CAN BUT PLEASE HELP ASAP ASAP

dalvyx [7]

(1) The ball is in the air for 1.4 seconds.

(2) The horizontal velocity of the ball as it rolls off the table is 6.32 m/s.

(3) The vertical velocity of the ball right before it hits the ground is 13.72 m/s.

(4) The horizontal velocity of the ball right before it hits the ground is 6.32 m/s.

(5) The initial vertical velocity as soon as the ball comes of the cliff is 13.72 m/s.

<h3>What is the time of motion of the ball?</h3>

The time of motion of the ball is calculated by applying the following equation.

t = √(2h/g)

where;

h is the height of the cliff
g is acceleration due to gravity

t = √(2h/g)

t = √(2 x 9.63 / 9.8)

t = 1.4 seconds

The horizontal velocity of the ball is calculated as follows;

v = d/t

where;

d is the horizontal distance travelled by the ball = 8.85 m

v = 8.85 m / 1.4 s

v = 6.32 m/s

The vertical velocity of the ball before it hits the ground is calculated as;

vf = vi + gt

vf = 0 + 9.8 x 1.4

vf = 13.72 m/s

The horizontal velocity of the ball right before it hits the ground is calculated as;

the initial velocity of a projectile = final horizontal velocity

vxf = vxi = 6.32 m/s

The initial vertical velocity as soon as the ball comes off the cliff = final vertical velocity = 13.72 m/s

Learn more about horizontal velocity here: brainly.com/question/24949996

#SPJ1

5 0

1 year ago

A tennis ball is dropped from 1.62 m above the

natita [175]

Answer:

-5.63 m/s

Explanation:

Given:

y₀ = 1.62 m

y = 0 m

v₀ = 0 m/s

a = -9.8 m/s²

Find: v

v² = v₀² + 2a (y − y₀)

v² = (0 m/s)² + 2(-9.8 m/s²) (0 m − 1.62 m)

v = -5.63 m/s

8 0

3 years ago

A physics teacher performing an outdoor demonstration suddenly falls from rest off a high cliff and simultaneously shouts help.

GrogVix [38]

Answer:

$H = 532 m$

Explanation:

When teacher falls into the cliff then she shout for Help at the same time

so here we know that sound will go down and reflect back up

so here in 3 s distance traveled by the sound

$d = vt$

$d = 340 \times 3$

$d = 1020 m$

now in the same time the distance that teacher will fall down is given as

$d_1 = \frac{1}{2}gt^2$

$d_1 = \frac{1}{2}(9.81)(3^2)$

$d_1 = 44.1 m$

now total distance traveled by teacher and sound in 3 s

$d_{total} = d + d_1$

$d_{total} = 1020 + 44.1$

this total distance must be equal to twice the height of the cliff

$2H = 1064.1 m$

$H = 532 m$

7 0

3 years ago

Read 2 more answers

Which of the following is the primary medium for beach erosion? ice gravity wind water

Fiesta28 [93]

I believe it is water that is the medium for beach erosion

3 0

3 years ago

Read 2 more answers

The Michelson-Morley experiment was designed to measure Group of answer choices the velocity of the Earth relative to the ether.

NISA [10]

Answer:

The Michelson-Morley was designed to detect the motion of the earth through the ether.

No such relation was found and the speed of light is assumed to be the same in all reference frames.

4 0

3 years ago