The reason behind the barking of the group of neighborhood dogs could be <u>Territorial/Protective</u> or <u>Alarm/Fear</u>.
What is bark or barking?
Dogs are known for making the most prevalent barking noises. Wolves, coyotes, foxes, seals, and barking owls are a few other creatures that make this sounds. The most typical onomatopoeia for this sound in English, particularly for large dogs, is "woof." The word "bark" can also be used to describe the sound made by numerous canids. A bark is a brief vocalization, as per the researchers at the University of Massachusetts Amherst.
Territorial/Protective: When a person or another animal enters their perceived area, your dog may bark excessively, depending on the breed. The barking frequently gets louder as the threat draws closer. When your dog barks in this manner, he will appear vigilant and sometimes even hostile.
Alarm/Fear: Some dogs will bark in alarm or fear at any sound or item that draws their attention or alarmed them. It's not just in their home country where this can occur. When they are afraid, their tails will be tucked and their ears will be pulled back.
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Answer:
airplane
Explanation:
as greater mass greater inertia
Answer:
Explanation:
Coordinate system is one that describe the location of an object in a given plane. It implies the use of axes (coordinates) and points.
Given that the man in the question walks 400 m due north of east. The cardinal points can be used in this case, with the north and east cardinals as the required axis.
scale =
=
=
scale = 1:40
This is a reduced scale which implies that 1 cm on the drawing is equal to 40 m on the original length.
The man's direction is north of east.
The graphical drawing of the vector is herewith attached to this answer.
Answer:
Free-fall is defined as the movement where the only force acting on an object is the gravitational force.
By the second Newton's law, we have that:
F = m*a
Where F = Force, m = mass, a = acceleration.
We can write this as:
a = F/m
And the gravitational force can be written as:
F = (G*M/r^2)*m
Where G is the gravitational constant, M is the mass of the Earth in this case, and r is the distance between both objects (the center of the Earth and the free-falling object)
As the radius of the Earth is really big, the term inside the parentheses is almost constant in the region of interest, then we can write:
G*M/r^2 ≈ g
And the gravitational force is:
F = g*m
And by the second Newton's law we had:
a = F/m = (g*m)/m = g
a = g
Then the acceleration does not depend on the mass of the object.
Then the thing that is common among the free-falling objects is the vertical acceleration.
Answer:
Explanation:
From the text of the complete problem found on internet, the expression of the force is:
The rate of change of F with respect to t can be find by calculating the derivative of F with respect to t.
First of all, let's recall the derivative of sine and cosine:
We have to calculate the derivative of a composite function, of the form
Its derivative is given by
By applying this formula to our expression, we find:
And by substituting the given data:
W = 45 lb
we find: