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1 answer:
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Answer:
a) = 4.67m/s
b) V = 8.29 m/s
Explanation:
Givens:
The bullet is 5.30g moving at 963m/s and its speed reduced to 426m/s. The wooden block is 610g.
a) From conservation of linear momentum
Pi = Pf
where are the mass and the initial velocity of the bullet,
and
are the mass and the initial velocity of the wooden block, and
and
are the final velocities of the wooden block and the bullet
The wooden block is initial at rest this yields
By solving for adn substitute the givens
=
=
= 4.67m/s
b) The center of mass speed is defined as
substituting:
V = 8.29 m/s
Explanation:
It is given that,
The ramp is tilted upwards at 25 degrees and Paul is pulling a large crate up the ramp with a rope that angles 10° above the ramp.
Total angle with respect to ramp is 35 degrees.
If Paul pulls with a force of 550 N.
The horizontal component of the force is given by :
The vertical component of the force is given by :
Hence, this is the required solution.
Answer:
v = 29.4 m / s
Explanation:
For this exercise we can use the conservation of mechanical energy
Lowest starting point.
Em₀ = K = ½ m v²
final point. Higher
= U = m g h
Let's use trigonometry to lock her up
cos 60 = y / L
y = L cos 60
Height is the initial length minus the length at the maximum angle
h = L - L cos 60
h = L (1- cos 60)
energy is conserved
Em₀ = Em_{f}
½ m v² = mgL (1 - cos 60)
v = 2g L (1- cos 60)
let's calculate
v² = 2 9.8 3.0 (1- cos 60)
v = 29.4 m / s