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saw5 [17]
3 years ago
8

___ is the sacrifice involved in making one decision over another

Chemistry
1 answer:
Scilla [17]3 years ago
4 0
Opportunity cost

Opportunity cost is the benefit, profit or value that could have been received or obtained but instead given up in favor of another alternative or course of action. Every situation has several alternatives and every resource has several alternative uses as well. Thus, every decision comes with it an opportunity cost. <span>
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Two important ways that energy is transported in the world around us is through
Ann [662]

Explanation:

The two ways that energy can be transferred are by doing work and by heat transfer.

5 0
3 years ago
An substance that is being dissolved by another object?​
Alex

Answer:

Solute - The solute is the substance that is being dissolved by another substance. In the example above, the salt is the solute. Solvent - The solvent is the substance that dissolves the other substance.

Explanation:

8 0
2 years ago
5 drops of 0.15 M Ki added to<br>40 drops of Na2S2O3<br>What is the final concentration of ki?​
rjkz [21]

Answer:

\boxed{\text{0.017 mol/L}}

Explanation:

Na₂S₂O₃ solution does not react with KI (it reacts with I₂), so it is simply diluting the KI, and we can use the dilution formula.

c_{1}V_{1} = c_{2}V_{2}

Data:

c₁ = 0.15 mol·L⁻¹; V₁ = 5 drops

V(Na₂S₂O₃) = 40 drops

Calculations:

(a) Calculate the total volume

V₂ = 5 + 40 = 45 drops

(b) Calculate the concentration

0.15 × 5 = c₂ × 45

0.75 = 45c₂

c_{2} = \dfrac{0.75 }{45} = \boxed{\textbf{0.017 mol/L}}

3 0
3 years ago
How can i figure out 2a and 2b?
krek1111 [17]

Answer:

u cant

Explanation:

7 0
2 years ago
Ethanol is produced industrially by the reaction of ethylene with water in the presence of an acid catalyst. How many grams of e
nikdorinn [45]

Answer: 249 grams

Explanation:

The balanced chemical equation is :

C_2H_4+H_2O\rightarrow C_2H_5OH

As water is present in excess , it is called as excess reagent and ethylene is the limiting reagent.

According to stoichiometry:

1 mole of ethylene produces = 1 mole of ethanol

Thus 5.40 mole of ethylene produces =\frac{1}{1}\times 5.40=5.40 mole of ethanol

Mass of ethanol = moles\times {\text {molar mass}}=5.40mol\times 46.07g/mol=249g

Thus 249 g of ethanol are produced from 5.40 mol of ethylene

8 0
3 years ago
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