Question

What is the equation of the line that is perpendicular to

Answer 1

Answer:

$y + x = 3$

Step-by-step explanation:

The question is poorly formatted. However, I will take the parameters as follows:

Given

Perpendicular to: J(-3,2) and L(2,7)

Passes through: (3,0)

Required

Write an equation for the line

First, calculate the slope (m) of JL

$m = \frac{y_2 - y_1}{x_2 - x_1}$

$m = \frac{7-2}{2+3}$

$m = \frac{5}{5}$

$m = 1$

Since the line is perpendicula4 to JL, the slope is:

$m_2 = -\frac{1}{m}$

$m_2 = -\frac{1}{1}$

$m_2 = -1$

The equation is then calculated using:

$y - y_1 = m(x - x_1)$

$y - 0 = -1(x - 3)$

$y - 0 = -x + 3$

$y = -x + 3$

$y + x = 3$