Honestly I believe the snail would travel 2.5 more centimeters in 6 minutes. so technically the snail traveled 12.5 cm in 6 minutes.
2x+9= 32
2x= 32-9
2x= 23
x= 23:2
x= 11.5
Answer:
3 7/12 kg
He doesn't have enough plant to feed strawberry 2 more times and tomato 1 more time
Step-by-step explanation:
On sunday , sheldon bought 4 1/2 kg of plant food. He uses 1 2/3 kg on his strawberry plants and used 1/4 kg for his tomato plants. b. Sheldon wants to feed his strawberry plants 2 more times and his tomato plants one more time. He will use the same amounts of plant food as before. How much plant food will be need? Does he have enough left to do so.
Total plant bought = 4 1/2 kg
Strawberry = 1 2/3 kg
Tomato = 1/4 kg
Strawberry + tomato
= 1 2/3 + 1/4
= 5/3 + 1/4
= 20+3/12
= 23/12 kg
Total remaining after Sunday
= Total - used
= 4 1/2 - 23/12
= 9/2 - 23/12
= 54-23/12
= 31/12
= 2 7/12 kg
Sheldon wants to feed his strawberry plants 2 more times and his tomato plants one more time.
Strawberry = 2 × 1 2/3
= 2 × 5/3
= 10/3 kg
Tomato = 1 × 1/4
= 1/4 kg
Total plant needed to feed strawberry two more times and tomato 1 more time
= 10/3 kg + 1/4 kg
= 40+3/12
= 43/12 kg
= 3 7/12 kg
He will need 3 7/12 kg of plant
He doesn't have enough plant to feed strawberry 2 more times and tomato 1 more time
316.7 gal = 2533.6 pints.
V = (4/3) pi r^3
9. V = (4/3)(3.14)(7.62)^3 = 1852.4 meters^3
10. V = (4/3)(3.14)(33/2)^3 = 18,807.0 inches^3
11. V = (4/3)(3.14)(18.4/2)^3 = 3260.1 feet^3
12. V = (4/3)(3.14)(sqrt3)/2)^3 = 2.7 cm^3
13. C = 2*pi*r ; 24 = 2 * 3.14 * r; 24/6.28 = r ; r = 3.82
V = (4/3)(3.14)(3.82)^3 = 233.4 in^3
14.V = (4/3)(3.14)(35.8)^3 = 192,095.6 mm^3
I can't read # 15 but follow the steps above.
