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77julia77 [94]
3 years ago
8

How is the stability of a nucleus affected by changing the number of nuclear particles?

Chemistry
1 answer:
Svet_ta [14]3 years ago
5 0

Answer:

Greatly affected.

Explanation:

The stability of a nucleus is greatly affected by changing the number of nuclear particles because changing the number of nuclear particles i.e. neutron or proton will leads to change the element. When we change the number of protons in an atom, we will change the atom from one element to a different element. Sometimes, when you add a proton to an element, the element will become radioactive in nature so we can conclude that changing number of nuclear particles impact the stability of nucleus of an atom.

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) how much of the primary standard benzoic acid (fm 122.12, density 1.27 g/ml) should you weigh out to obtain a 100.0 mm aqueous
aniked [119]
We must know that molarity is a unit for concentration and it is expressed as:

molarity = moles / liters

The molarity is 100 millimolar, or 0.1 molar. The volume is 250 ml, or 0.25 liters. Using the formula above, we find the moles of benzoic acid required.

moles = molarity * liters
moles = 0.1 * 0.25
moles = 0.025

Next, we know that the molar mass for benzoic acid is 122.12 g/mol and the moles of a substance are given by:
moles = mass / molar mass

mass = moles * molar mass
mass = 0.025 * 122.12
mass = 3.05 grams

You will need to weigh out 3.05 grams of benzoic acid
8 0
3 years ago
Assuming the materials don't mix, show how the materials would "stack up" in a graduated cylinder. (Based on their densities) (J
o-na [289]

Explanation:

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6 0
3 years ago
Which of these is not a challenge an organism encounters
bekas [8.4K]
Staying healthy
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6 0
4 years ago
Read 2 more answers
How many moles are equal to 1.2 x 10^21 molecules of lithium?
Shtirlitz [24]
1 mole --------------------------- 6.02 x 10²³ molecules
( moles lithium ) --------------- 1.2 x 10²¹ molecules

( moles lithium ) = (1.2 x 10²¹ ) x 1  / ( 6.02 x 10²³ )

= 1.2 x 10²¹ / 6.02 x 10²³

= 2.0 x 10⁻³ moles of lithium

Answer D

hope this helps!
4 0
3 years ago
Use this reaction: 3NaOH + H3PO4--> Na3PO4 + 3H20
uranmaximum [27]
The balanced reaction would be as follows:

<span>3NaOH + H3PO4 --> Na3PO4 + 3H20

We are given the concentration and the amount of the reactants to be used. We use these values for the calculations as follows:

</span><span>How many mL of .225 M NaOH will react with 4.568g H3PO4? 

4.568 g (1 mol / 98 g) ( 3 mol NaOH / 1 mol H3PO4 ) ( 1 L / .225 mol NaOH ) = 0.621 L or 621 mL of .225 NaOH</span>
8 0
3 years ago
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