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Montano1993 [528]
3 years ago
9

How many molecules (or formula units) are in 138.56 g C4H10 Express your answer using four significant figures.

Chemistry
1 answer:
Semenov [28]3 years ago
7 0

Answer:

dont buy cheap and off we went

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What is the formula for the binary ionic compound formed between<br> zinc and nitrogen.
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Answer: Zinc nitride (Zn3N2) is an inorganic compound of zinc and nitrogen, usually obtained as (blue)grey crystals. It is a semiconductor. In pure form, it has the anti-bixbyite structure.

Chemical formula: Zn3N2

Space group: Ia-3, No. 206

EC Number: 215-207-3

Appearance: blue-gray cubic crystals

Explanation:

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2 years ago
What is the ΔG for the following reaction at 25°C?
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\Delta G_{global}=\Delta G_{products}-\Delta G_{reagents}\\\\&#10;\text{We should consider the stoichiometry:}\\\\&#10;\Delta G=2\Delta G_{NO_2}-\Delta G_{N_2O_4}\\\\&#10;\Delta G=2\cdot51.8-98.28=103.6-98.28\\\\&#10;\boxed{\Delta G=5.32~kJ}
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2 years ago
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T, F, T, T, F



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4 0
3 years ago
List out the effects seen inplants due to lack of phosphorus.​
valkas [14]

Answer:

Plants normally turn dark green and look stunted (both leaves and stalks). Older leaves are first affected and may become violet. Sometimes the brown tips of the leaves remain fragile and their maturity seems to be delayed.

Explanation:

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4 0
2 years ago
Phthalates used as plasticizers in rubber and plastic products are believed to act as hormone mimics in humans. The value of ΔHc
jeka94

Answer:

T_f = 25.05°C

Explanation:

Given:

the value of ΔHcomb (heat of combustion) for dimethylphthalate (C10H10O4) is = 4685 kJ/mol.

mass = 0.905g of dimethylphthalate

molar mass = 194.18g dimethylphthalate

number of moles of dimethylphthalate = ???

T_i = 21.5°C

C_{calorimeter} = 6.15 kJ/°C

T_f = ???

since we have our molar mass and mass of dimethylphthalate ;we can determine the number of moles as;

0.905g of dimethylphthalate ×  \frac{1 mole (dimethylphthalate)}{194.184g(dimethylphthalate)}

number of moles of dimethylphthalate = 0.000466 moles

Heat released = moles of dimethylphthalate × heat of combustion

=  0.000466 moles × 4685 kJ

= 21.84 kJ

∴ Heat absorbed by the calorimeter =  C_{calorimeter} (T_f-T_i} )

21.84 kJ =6.15 kJ/°C * (T_f-21,5^0C)

21.84 KJ = (6.15 kJ/^0C * T_f) - (6.15 kJ/^0C*21.5^0C)

21.84 KJ = (6.15 kJ/^0C * T_f) - 132.225 kJ

21.84 KJ + 132.225 kJ = (6.15 kJ/^0C * T_f)

154.065 kJ = (6.15 kJ/^0C * T_f)

T_f = \frac{154.065kJ}{6.15kJ/^0C}

T_f =25.05°C

4 0
3 years ago
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