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Nataliya [291]
3 years ago
5

A gas has a volume of 543 ml. at a temperature of 75.0°C. What volume will the gas occupy at 20.2°C?

Chemistry
1 answer:
alexandr1967 [171]3 years ago
5 0

Answer:

V₂ = 457.49 mL

Explanation:

Given that,

Initial volume, V_1=543\ mL

Initial temperature, T_1=75^{\circ} C=75+273=348\ K

Final temperature, T_2=20.2^{\circ} C=20.2+273=293.2\ K

We need to find the final volume of the gas. The relation between the volume and the temperature of the gas is given by :

\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}

Put the respected values,

V_2=\dfrac{V_1T_2}{T_1}\\\\V_2=\dfrac{543\times 293.2}{348}\\\\V_2=457.49\ mL

So, the final volume of the gas is equal to 457.49 mL.

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What volume of 0.4567 m h2so4 is required to neutralize 30.00 ml of 0.3210 m naoh?
sertanlavr [38]
Answer is: volume of H₂SO₄ is 42.1 mL.<span>
Chemical reaction: H</span>₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O.<span>
c(H</span>₂SO₄) = 0,4567 M = 0,4567 mol/L.<span>
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n(NaOH) = c(NaOH) · V(NaOH).
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n(H</span>₂SO₄) = 0,01926 mol.<span>
V(H</span>₂SO₄) = n(H₂SO₄) ÷ c(H₂SO₄).<span>
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