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Nataliya [291]
2 years ago
5

A gas has a volume of 543 ml. at a temperature of 75.0°C. What volume will the gas occupy at 20.2°C?

Chemistry
1 answer:
alexandr1967 [171]2 years ago
5 0

Answer:

V₂ = 457.49 mL

Explanation:

Given that,

Initial volume, V_1=543\ mL

Initial temperature, T_1=75^{\circ} C=75+273=348\ K

Final temperature, T_2=20.2^{\circ} C=20.2+273=293.2\ K

We need to find the final volume of the gas. The relation between the volume and the temperature of the gas is given by :

\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}

Put the respected values,

V_2=\dfrac{V_1T_2}{T_1}\\\\V_2=\dfrac{543\times 293.2}{348}\\\\V_2=457.49\ mL

So, the final volume of the gas is equal to 457.49 mL.

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Answer:

Explanation:

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p=m*v

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Which of the following pairs of elements is most likely to share one or more pairs of electrons between their nuclei?
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2 years ago
What mass of propane could burn in 48.0 g of oxygen? C3H8 + 5O2 → 3CO2 + 4H2O
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Answer:

Mass = 13.23 g  

Explanation:

Given data:

Mass of oxygen = 48.0 g

Mass of propane burn = ?

Solution:

Chemical equation:

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Number of moles of oxygen:

Number of moles = mass/molar mass

Number of moles = 48.0 g/ 32 g/mol

Number of moles = 1.5 mol

now we will compare the moles of propane and oxygen.

              O₂           :          C₃H₈

               5            :            1

             1.5            :          1/5×1.5 = 0.3 mol

Mass of propane burn:

Mass = number of moles × molar mass

Mass = 0.3 mol × 44.1 g/mol

Mass = 13.23 g  

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