Answer:
A - 0%
B- 50%
C- 50%
D- 100%
Step-by-step explanation:
Cystic fibrosis is inherited in an autosomal recessive form, meaning that a person has to inherit two abnormal genes for the disease to manifest. In the case of this question, one parent is a gene carrier, so his genotype is Aa, while the other does not have the cystic fibrosis gene, so AA.
Performing the cross of Aa x AA, we can see that:
a.) The probability of a child would have cystic fibrosis is 0%, since the disease is recessive and to be affected it should receive a recessive gene from each parent.
b.) The probability of a child would be a carrier is 50%, as 50% of the crossing phenotypes are Aa.
c.) The probability of a child would not have cystic fibrosis and is not a carrier is 50%, as 50% of the child's genotype is AA.
d.) The probability of a child would be healthy is 100%, as of all possible phenotypes none is affected.
Answer:
15
Step-by-step explanation:
since it is a square all sides are equal.
60/4=15
Therefore the answer is 15
Option A: drop of 8 meters would be correct because a drop in this case indicates something has been removed. -8 equals 8 below 0.
Answer:
number 1 is 5x+8y+10
Step-by-step explanation:
Let's simplify step-by-step.
10y+3x+10+x+x−2y
=10y+3x+10+x+x+−2y
Combine Like Terms:
=10y+3x+10+x+x+−2y
=(3x+x+x)+(10y+−2y)+(10)
=5x+8y+10
Answer:
=5x+8y+10
