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iren [92.7K]
3 years ago
8

Can a stable compound be made from lithium and oxygen

Chemistry
2 answers:
Crazy boy [7]3 years ago
8 0

Answer:

No, because oxygen wants two electrons to become stable and lithium will only give up 1 electron.

melamori03 [73]3 years ago
5 0
The Ionic Bond formation for Lithium Oxide. Lithium is in group 1 of the periodic table. A lithium atom will lose 1 electron to form a stable 1+ ion. An oxygen atom will gain 2 electrons to form a stable 2- ion.
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How can valence electrons be used to predict the type of compounds formed?
Alex17521 [72]
Valence electrons are the electrons in the outermost shell. Those are t<span>he electrons on an atom that can be gained or lost in a chemical reaction.
</span>Elements that are left on the periodic table <span> have relatively few </span>valence electrons<span>, and can form ions  more easily by losing their </span>valence electrons<span> to form positively charged cations.</span>
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3 years ago
Analyze the food web. If the frog population decreases, what impact will this likely have on the food web?
sergiy2304 [10]

Answer:

the population of grasshoppers will decrease

Explanation:

a food source is becoming more and more limited thus, its predator will also start to die out due to starvation

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3 years ago
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What benefits does sweet n low have
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Answer:

The health hazard warning label on Sweet ‘N Low packets has been removed, however, dangers may still lurk. According to the FDA, saccharin has been linked to bladder cancer in laboratory animals which prompted them to require warning labels on products containing this artificial sweetener in 1977.

Explanation:

6 0
3 years ago
State the Third Law of Motion on the basis of the Third law explain the following [a] A boat tend to leave the shore when passen
Firlakuza [10]
C because it has to do with opposite motions and stuff
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3 years ago
An enzyme with molecular weight of 310 kDa undergoes a change in shape when the substrate binds. This change can be characterize
oee [108]

Answer:

(a) r = 6.26 * 10⁻⁷cm

(b) r₂ = 6.05 * 10⁻⁷cm

Explanation:

Using the sedimentation coefficient formula;

s =  M(1-Vρ) / Nf ; where s is sedimentation coefficient, M is molecular weight, V is specific volume of protein, p is density of the solvent, N is Avogadro number, f if frictional force = 6πnr, n is viscosity of the medium, r is radius of particle

s = M ( 1 - Vρ) / N*6πnr

making r sbjct of formula, r =  M (1 - Vρ) / N*6πnrs

Note: S = 10⁻¹³ sec, 1 KDalton = 1 *10³ g/mol, I cP = 0.01 g/cm/s

r = {(3.1 * 10⁵ g/mol)(1 - (0.732 cm³/g)(1 g/cm³)} / { (6.02 * 10²³)(6π)(0.01 g/cm/s)(11.7 * 10⁻¹³ sec)

r = 6.26 * 10⁻⁷cm

b. Using the formula r₂/r₁ = s₁/s₂

s₂ = 0.035 + 1s₁ = 1.035s₁

making r₂ subject of formula; r₂ = (s₁ * r₁) / s₂ = (s₁ * r₁) / 1.035s₁

r₂ = 6.3 * 10⁻⁷cm / 1.035

r₂ = 6.05 * 10⁻⁷cm

8 0
3 years ago
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