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Ipatiy [6.2K]
3 years ago
9

SOMEONE PLS HELP ME ITS URGENT

Chemistry
2 answers:
stiks02 [169]3 years ago
7 0

Answer:

copper is less reactive than iron

Explanation:

=>According to the reactivity series of metals copper is the least reactive metal thus is displaced by iron

Simora [160]3 years ago
5 0

If copper is heated with iron oxide there is no obvious reaction because

copper is less reactive than iron.

On a reactivity chart, copper is far below iron. This makes it impossible for a replacement reaction to occur, so the equation doesn't change.

I hope I helped!

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Nitric acid (HNO3) is a strong acid that is completely ionized in aqueous solutions of concentrations ranging from 1% to 10% (1.
Alborosie

<u>Given:</u>

Concentration of HNO3 = 7.50 M

% dissociation of HNO3 = 33%

<u>To determine:</u>

The Ka of HNO3

<u>Explanation:</u>

Based on the given data

[H+] = [NO3-] = 33%[HNO3] = 0.33*7.50 = 2.48 M

The dissociation equilibrium is-

            HNO3   ↔    H+      +      NO3-

I            7.50               0                 0

C          -2.48          +2.48              +2.48

E            5.02            2.48              2.48

Ka = [H+][NO3-]/HNO3 = (2.48)²/5.02 = 1.23

Ans: Ka for HNO3 = 1.23

6 0
3 years ago
<img src="https://tex.z-dn.net/?f=plz%20%5C%3A%20help%20%20%5C%3A%20me%20%5C%3A%20it%20%5C%3A%20is%20%5C%3A%20due%20%5C%3A%202mo
Sophie [7]

Answer:

hi.

Explanation:

1. B

2. C

3. A

4. B

5.B

hope this helps

5 0
3 years ago
Which of the following is part of photosynthesis, but not part of cellular respiration?
Licemer1 [7]

Answer:

A

Explanation:

  • plants need sunlight to eat. so that's why

8 0
3 years ago
Calculate the following quantity: molarity of a solution prepared by diluting 45.45 mL of 0.0404 M ammonium sulfate to 550.00 mL
dybincka [34]

Answer:

M_2=3.34x10^{-3}M

Explanation:

Hello!

In this case, since a dilution process implies that the moles of the solute remain the same before and after the addition of diluting water, we can write:

M_1V_1=M_2V_2

Thus, since we know the volume and concentration of the initial sample, we compute the resulting concentration as shown below:

M_2=\frac{M_2V_2}{V_1} =\frac{45.45mL*0.0404M}{550.00mL}\\\\M_2=3.34x10^{-3}M

Best regards!

5 0
2 years ago
Is sugar ( in water) an example of an element or compound
tresset_1 [31]

Answer:

A compound

Example:

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8 0
3 years ago
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