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iren2701 [21]
3 years ago
8

A block is pulled 0.90 m to the right in 4.5 s. What is the block's average speed to the nearest tenth of m/s?

Chemistry
2 answers:
pshichka [43]3 years ago
8 0

Answer:

-

Explanation:

jeka57 [31]3 years ago
5 0

Answer:

The average speed of the blocks are 0.36 m/s.

Explanation:

Average speed is defined as the ratio of distance covered per unit time. So if it is said that blocks are pulled to 0.9 m in the right side. This means the blocks cover a distance of 0.9 m from the origin and that distance is covered in 2.5 s. Thus, the average speed can be calculated from the change in speed with respect to time. As at time t = 0 , the speed is also zero, and at time t = 2.5 s , the speed will be.

Since, in this case, the speed is equal to the average speed of blocks. So the average speed of the blocks will be 0.36 m/s.

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7 0
4 years ago
How many molecules are in 3cacl2
Travka [436]

Answer:

The molar mass and molecular weight of 3CaCl2 is 332.952. 

5 0
3 years ago
The enthalpy of solution (∆H) of KOH is -57.6 kJ/mol. If 3.66 g KOH is dissolved in enough water to make a 150.0 mL solution, wh
Wewaii [24]

When 3.66 g of KOH (∆Hsol = -57.6 kJ/mol) is dissolved in 150.0 mL of solution, it causes a temperature change of 5.87 °C.

The enthalpy of solution of KOH is -57.6 kJ/mol. We can calculate the heat released by the solution (Qr) of 3.66 g of KOH considering that the molar mass of KOH is 56.11 g/mol.

3.66g \times \frac{1mol}{56.11g} \times \frac{(-57.6kJ)}{mol} = -3.76 kJ

According to the law of conservation of energy, the sum of the heat released by the solution of KOH (Qr) and the heat absorbed by the solution (Qa) is zero.

Qr+Qa = 0\\\\Qa = -Qr = 3.76 kJ

150.0 mL of solution with a density of 1.02 g/mL were prepared. The mass (m) of the solution is:

150.0 mL \times \frac{1.02g}{mL}  = 153 g

Given the specific heat capacity of the solution (c) is 4.184 J/g・°C, we can calculate the change in the temperature (ΔT) of the solution using the following expression.

Qa = c \times m \times \Delta T\\\\\Delta T = \frac{Qa}{c \times m} = \frac{3.76 \times 10^{3}J  }{\frac{4.184J}{g.\° C }  \times 153g} = 5.87 \° C

When 3.66 g of KOH (∆Hsol = -57.6 kJ/mol) is dissolved in 150.0 mL of solution, it causes a temperature change of 5.87 °C.

Learn more: brainly.com/question/4400908

7 0
2 years ago
8. If I have 34 grams of FeO, how many grams of Oxygen were synthesized?<br>Fe + O2 → Feo​
krek1111 [17]

Answer:

34 gram of FeO produced 8 gram of oxygen.

Explanation:

Given data:

Mass of FeO = 34 g

Mass of oxygen = ?

Solution;

Chemical equation:

2FeO → 2Fe + O₂

Number of moles of FeO:

Number of moles = mass/ molar mass

Number of moles = 34 g /71.8 g/mol

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Now we will compare the moles of FeO with oxygen:

             FeO       :       O₂

                2         :        1

                0.5      :      1/2 × 0.5 = 0.25

Mass of oxygen:

Mass = number of moles × molar mass

Mass =  0.25 mol × 32 g/mol

Mass = 8 g

So 34 gram of FeO produced 8 gram of oxygen.

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Answer:

0.96

Explanation:

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