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iren2701 [21]
3 years ago
8

A block is pulled 0.90 m to the right in 4.5 s. What is the block's average speed to the nearest tenth of m/s?

Chemistry
2 answers:
pshichka [43]3 years ago
8 0

Answer:

-

Explanation:

jeka57 [31]3 years ago
5 0

Answer:

The average speed of the blocks are 0.36 m/s.

Explanation:

Average speed is defined as the ratio of distance covered per unit time. So if it is said that blocks are pulled to 0.9 m in the right side. This means the blocks cover a distance of 0.9 m from the origin and that distance is covered in 2.5 s. Thus, the average speed can be calculated from the change in speed with respect to time. As at time t = 0 , the speed is also zero, and at time t = 2.5 s , the speed will be.

Since, in this case, the speed is equal to the average speed of blocks. So the average speed of the blocks will be 0.36 m/s.

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A 25.0-mL sample of an H2SO4 solution requires 50.0 mL of 0.150 M NaOH to completely react with the H2SO4. What was the concentr
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V( H₂SO₄) = 25.0 mL in liters = 25.0 / 1000 = 0.025 L
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number of moles NaOH :

n = M x V

n = 0.150 x <span> 0.05 
</span>
n = 0.0075 moles of NaOH 

H₂SO₄(aq) + 2 NaOH(aq) = Na₂SO₄(aq) + 2 H₂O(l)

1 mole H₂SO₄ ---------- 2 mole NaOH
? mole H₂SO₄ ---------- 0.0075 moles NaOH

moles = 0.0075 * 1 / 2

= 0.00375 moles of H₂SO₄

M(H₂SO₄) = n / V

M = 0.00375 / <span> 0.025

</span>= 0<span>.15 M
</span>
hope this helps!

8 0
3 years ago
Giving brainliest ✅✅
34kurt

Answer:

A

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<span>Gibbs free energy (G) determines if reaction will proceed spontaneously.
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4 0
3 years ago
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