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Ainat [17]
3 years ago
5

Simplify the expression (2x² + 9) (x² - 7)​

Mathematics
2 answers:
Natali5045456 [20]3 years ago
7 0

Answer:

2x^{4} - 5x² - 63

Step-by-step explanation:

Given

(2x² + 9)(x² - 7)

Each term in the second factor is multiplied by each term in the first factor, that is

2x² (x² - 7) + 9(x² - 7) ← distribute both parenthesis

= 2x^{4} - 14x² + 9x² - 63 ← collect like terms

= 2x^{4} - 5x² - 63

Mashutka [201]3 years ago
6 0

Answer:

\boxed {2x^{4} - 5x^{2} - 63}

Step-by-step explanation:

Solve the following expression:

(2x^{2} + 9) (x^{2} - 7)

-Use <u>Distributive Property</u>:

(2x^{2} + 9) (x^{2} - 7)

2x^{4} - 14x^{2} + 9x^{2} - 63

-Combine like terms:

2x^{4} - 14x^{2} + 9x^{2} - 63

\boxed {2x^{4} - 5x^{2} - 63}

Therefore, the final answer is 2x^{4} - 5x^{2} - 63.

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1) f(x) = 2x + 4, g(x) = 4x2 + 1; Find (g ∘ f)(0).
Sholpan [36]

Answer:

<h2>(g \: \circ \: f)(0) = 17</h2>

Step-by-step explanation:

f(x) = 2x + 4

g(x) = 4x² + 1

In order to find (g ∘ f)(0) we must first find

(g ° f )(x)

To find (g ° f )(x) substitute f(x) into g(x) that's for every x in g(x) replace it with f(x)

That's

<h3>(g \: \circ \: f)(x) = 4( ({2x + 4})^{2} ) + 1 \\  = 4(4 {x}^{2}  + 16x + 16) + 1 \\  =  {16x}^{2}  + 64x + 16 + 1</h3>

We have

<h3>(g \: \circ \: f)(x) =  {16x}^{2}  + 64x + 17 \\</h3>

Now to find (g ∘ f)(0) substitute the value of x that's 0 into (g ∘ f)(0)

We have

<h3>(g \: \circ \: f)(0) = 16( {0})^{2}  + 64(0) + 17 \\</h3>

We have the final answer as

<h3>(g \: \circ \: f)(0) = 17</h3>

Hope this helps you

8 0
4 years ago
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