Cotx +Coty/tany +tanx

Which is an example of continuous data?

azamat

Answer:

The weight of newborn babies or The temperature of a freezer

Step-by-step explanation:

anything measuring numbers

5 0

3 years ago

Help asap please!! 50 points and BRAINLIEST!!! Thank you!!

netineya [11]

Answer:

Like radicals are radicals that have the same number in the radical sign

So it would be 3√7 and 11√7 (reasoning is they both have a 7 underneath the radical sign)

For the second one Simplify: 35√11-√11

you want to subtract like normal 35√11-1√11, (since there isn't a number there we are going to put one)

35-1=34

34√11, You want to keep the √11, because it is like having like terms but instead of variables it is √

34√11

The third one: Simplify: 15√6+3√6

we want to do the same thing as the problem above so,

15+3=18

18√6, again you want to keep the radical the same

18√6

For the fourth one: 5√7+√7-2√7

you want to do one step at a time so

5√7+√7= 6√7 (again you would have a one in front of the √7, then you would keep your radicals the same)

Then you want to subtract that to your other one

6√7-2√7= 4√7

6-2=4, (again keep the radical the same)

4√7

For the last one

3√5*√10+11√5*√10-√5

You always want to multiply first as in PEMDAS

Lets take this one step at a time also

First 3√5*√10

When multiplying radicals you would multiply like normal

3√50 (√5*√10= √50)

3√50

Now lets do 11√5*√10

again √5*√10=√50

so 11√50

Now you are going to add your two answers together

3√50+11√50= 14√50 (you would add 3+11=14, keep the radicals the same)

Don't forget about your -√5

14√50-√5, this as simplified as you can get so your answer is

14√50-√5

I hope this helps you ;)

Step-by-step explanation:

4 0

3 years ago

Estimate the solution to the system of equations.

Leona [35]

Answer:

$\sf C) \ x = -1\dfrac{2}{5} , \ y = \ 1\dfrac{3}{5}$

Given equations:

a) -3x + 3y = 9

b) 2x - 7y = -14

Make x the subject in equation 1:

-3x + 3y = 9

-3x = 9 - 3y

x = y - 3

Substitute this into equation 2:

2(y - 3) - 7y = -14

2y - 7y = -14 + 6

-5y = -8

y = -8/-5

y = 1.6

Then x = y - 3

= 1.6 - 3

= -1.4

Solution: (x, y) ⇒ (-1.4, 1.6)

3 0

2 years ago

i don't understand how to make it into a graphing form? how do you find the center and radius? (I'm confused because it has a 4x

Vilka [71]

Answer: $\bold{(x-2)^2+(y-3)^2=\dfrac{1}{4}}$

Center = (2, 3) radius = $\bold{\dfrac{1}{2}}$

Step-by-step explanation:

When both the x² and y² values are equal and positive, the shape is a circle. Complete the square to put the equation in format:

(x-h)² + (y-k)² = r² where

(h, k) is the vertex
r is the radius

1) Group the x's and y's together and move the number to the right side

4x² - 16x + 4y² - 24y = -51

2) Factor out the 4 from the x² and y²

4(x² - 4x ) + 4(y² - 6y ) = -51

3) Complete the square (divide the x and y value by 2 and square it)

$4[x^2-4x+\bigg(\dfrac{-4}{2}\bigg)^2]+4[y^2-6y+\bigg(\dfrac{-6}{2}\bigg)^2]=-51+4\bigg(\dfrac{-4}{2}\bigg)^2+4\bigg(\dfrac{-6}{2}\bigg)^2$

= 4(x - 2)² + 4(y - 3)² = -51 + 4(-2)² + 4(-3)²

= 4(x - 2)² + 4(y - 3)² = -51 + 4(4) + 4(9)

= 4(x - 2)² + 4(y - 3)² = -51 + 16 + 36

= 4(x - 2)² + 4(y - 3)² = 1

4) Divide both sides by 4

$(x-2)^2+(y-3)^2=\dfrac{1}{4}$

(h, k) = (2, 3)
$r=\dfrac{1}{2}$

6 0

3 years ago

2r + 1.6b = 10 but r is independent variable

kipiarov [429]

Answer:

it's either B=6.25-1.25r or it's r=5-0.8b

8 0

3 years ago