Answer:
Step-by-step explanation:
Hello,
<em>"Ray says the third-degree polynomial has four intercepts. Kelsey argues the function can have as many as three zeros only."</em>
We know that Kelsey is right, a polynomial of degree 3 has maximum 3 zeroes, so it means that the graph of this polynomial has maximum 3 x-intercepts.
<u>So how Ray can be right too?</u>
we need to think of y-intercept, if we add the y-intercept then Ray can be right too,
as you can see in one example below
there are 3 x-intercepts and 1 y-intercept.
This being said, Ray is not always right. For instance 
has only 1 zero (multiplicity 3) its graph has only 1 intercept in the point (0,0)
hope this helps
the discriminant formula is b^2-4ac
so plug the values from each equation into the formula and solve, the result is the value of the discriminant
if the number is negative, there are no real roots/x-int
if it is 0 there is one real root/x-intercepts
if it is positive it has 2 real roots/x-int
and to find the actual solutions you have to plug the values into the quadratic formula
I think it’s 96 I might be wrong sorry if I am
Answer:
1) 0.9, 0.99, 0.09, 0.0009
2) 4(2x²+9x)
3) 110
4) $9.50 per pizza
5) 23