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maks197457 [2]
2 years ago
11

Four less than the product of 2 and a number equals 3 as an equation

Mathematics
1 answer:
Mademuasel [1]2 years ago
8 0

Answer:

4-2x=3

Step-by-step explanation:

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Which statements are true about the number represented by the blocks? Check all that apply.
chubhunter [2.5K]

Answer:

alllllllll

Step-by-step explanation:

5 0
3 years ago
Help I will be marking brainliest!!
lora16 [44]

Answer:

<u>Given</u>: base = 10.4ft, height = 12.5

Area of octagon = 8(1/2 × b × h)

  • 8(1/2 × 10.4 × 12.5)
  • 520ft²

Volume of pool = 520ft² × 3ft

  • 1560ft³

Now, 1 cubic ft takes 7.5 gallons to fill.

Therefore, 1560 cubic ft takes,

  • 1560 × 7.5
  • 11700

So, <u>Correct choice</u> - [D] 11,700.

5 0
3 years ago
What is 1 1/3 as a improper fraction
Mumz [18]
Okay so for this all you have to do is add 1 to 1/3.

However, to do this you first need to convert 1 into a fraction.

1 = 3/3
3/3 + 1/3 = 4/3

Hope this helps :)
8 0
2 years ago
A series of three? separate, adjacent tunnels is constructed through a mountain. Its length is approximately 25 kilometers. Each
Nadya [2.5K]

Answer:

312.5\pi \text{ km}^3\approx 981.75\text{ km}^3

Step-by-step explanation:

We have been given that a series of 3 separate, adjacent tunnels is constructed through a mountain. Its length is approximately 25 kilometers.

Each of the three tunnels is shaped like a half-cylinder with a radius of 5 meters.

Since we know that volume of a semicircular or a half cylinder is half the volume of a circular cylinder.

\text{Volume of a semicircular cylinder}=\frac{\pi r^2h}{2}, where,

r = Radius of cylinder,

h = height of the cylinder.

Upon substituting our given values in volume formula we will get,

\text{Volume of a semicircular cylinder}=\frac{\pi (5\text{ km})^2*25\text{ km}}{2}

\text{Volume of a semicircular cylinder}=\frac{\pi*25\text{ km}^2*25\text{ km}}{2}

\text{Volume of a semicircular cylinder}=\frac{\pi*625\text{ km}^3}{2}

\text{Volume of a semicircular cylinder}=\pi*312.5\text{ km}^3

\text{Volume of a semicircular cylinder}=\pi*312.5\text{ km}^3

\text{Volume of a semicircular cylinder}=981.74770\text{ km}^3

Therefore, the volume of earth removed to build the three tunnels is 312.5\pi \text{ km}^3\approx 981.75\text{ km}^3.


4 0
3 years ago
What is the 13 times tables
tensa zangetsu [6.8K]
0 X 13 = 0
1 X 13 = 13
2 X 13 = 26
3 X 13 = 39
4 X 13 = 52
5 X 13 = 65
6 X 13 = 78
7 X 13 = 91
8 X 13 = 104
9 X 13 = 117
10 X 13 = 130
11 X 13 = 143
12 X 13 = 156
13 X 13 = 169
14 X 13 = 182
15 X 13 = 195
16 X 13 = 208
17 X 13 = 221
18 X 13 = 234
19 X 13 = 247
<span>20 X 13 = 260</span>
7 0
3 years ago
Read 2 more answers
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