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Kazeer [188]
3 years ago
9

PLEASE ANSWER

Chemistry
1 answer:
kirza4 [7]3 years ago
7 0

Answer:

1) solid

2)liquid

3)gas

4)plasma

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24 g of magnesium to mol
sergey [27]

Explanation:

mole = mass/ molar mass

mass= 24g

molar mass = 24g/mol

mole = 24g/ 24g/mol

= 1 mole

7 0
3 years ago
What is the henry's law constant for co2 at 20∘c? express your answer to three significant figures and include the appropriate u
Gennadij [26K]
Actually, Henry's Law is an empirical value. It means that it was not obtained out of raw calculations or correlations. This was gathered from experimental results. Hence, you can search its data. At standard temperature of 25°C (298 K),

k = k°e^[2400(1/T - 1/T°)], where k° = 29.4 L·atm/mol
Substituting the values so that T would be in 20°C or 293 K,
k = (29.4 L·atm/mol)e^[2400(1/293 - 1/298)]
k = 33.7 L·atm/mol
3 0
3 years ago
Read 2 more answers
consider the substance:carbon dioxide, gold, bronze, alcohol, iron, and, oxygen.from the list , select the substances that :(1)
lbvjy [14]

Answer:

Oxygen

Explanation:

 · Air decolorization makes use of chromophores’ instability on oxygen to decolorize the oil by air-oxidizing pigments. For example, the carotenoid and chlorophyll in the oil are very unstable because of their structure, which is easy to be discolored under the action of oxygen. However, air decolorization leads to thermal oxidation of the oil, too.

5 0
3 years ago
The atomic mass of oxygen is 15.999 amu whatbdoes the value equal
sweet-ann [11.9K]

Answer:

The sum of the protons and neutrons.

Explanation:

protons + neutrons = atomic mass

7 0
3 years ago
You have just isolated a new radioactive element. If you can determine its half-life, you will win the Nobel Prize in physics. Y
lbvjy [14]

Answer: 2.58 days

Explanation:

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant  = ?

t = age of sample  = 6 days

a = initial amount of the reactant  =  1 g

a - x = amount left after decay process   = 0.2 g

a) to find the rate constant

6=\frac{2.303}{k}\log\frac{1.0}{0.2}

k=\frac{2.303}{6}\log\frac{1.0}{0.2}

k=0.268days^{-1}

b) for completion of half life:  

Half life is the amount of time taken by a radioactive material to decay to half of its original value.

t_{\frac{1}{2}}=\frac{0.693}{k}

t_{\frac{1}{2}}=\frac{0.693}{0.268}=2.58days

The half life is 2.58 days

3 0
3 years ago
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