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Ksivusya [100]
3 years ago
8

Pleaseeeeeefgghhbbbbbbbbbb

Chemistry
1 answer:
ehidna [41]3 years ago
5 0
<h2>Hey There!</h2><h2>_____________________________________</h2><h2>Answer:</h2><h2>----------------------------------------------------------------------</h2><h2>ELECTROPLATING </h2>

Electroplating the plating one metal on to the another metal, It is mostly used for preventing corrosion by using copper or chromium or decorate the object by using gold or silver plating.

__________________________________________________________

<h3>Principle:</h3>

When electricity is passed the thin layer of metal is deposited on another metal and water molecule given out as a By-Product, Thus this process works on the principle of Hydrolysis.

<h2>_____________________________________</h2><h2>QUESTION:</h2>

A) Electrolysis

B) Chromium prevents corrosion and gives the fine shining touch to the objects.

C) The metal which is deposited to the object i.e. spoon will be connected to the positive electrode of a battery, Thus it is anode. The spoon at which electroplating is need to be done is connected to the negative electrode, thus the Spoon is cathode.

<h2>_____________________________________</h2><h2>Best Regards,</h2><h2>'Borz'</h2>

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How to balance this equation
Svetlanka [38]

Answer:

2Al + 3Ni(SO4) ------->   1Al2(SO4)3 +  2Ni

Explanation:

7 0
3 years ago
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Which element is the excess reagent when 3.00 moles of Mg is ignited in 2.20 moles of pure oxygen
Artyom0805 [142]

Answer:

Oxygen is in excess.

Explanation:

The coefficients of the balanced equation create a mole ratio that shows the ratio of how many reactants are used up and products are created.  

The mole ratio of Mg to O2 in this equation is 2:1, which means that for every two moles of Mg used, there will be 1 mole of O2 used.

If we have 3.00 moles of Mg, we will only need 1.5 moles of oxygen to completely burn the Mg. Therefore, when all 3.00 moles of Mg are used, there will still be some of the 2.20 moles of oxygen remaining.

7 0
3 years ago
When 3243. grams of iron (III) chloride are reacted with 511.8 grams of hydrosulfuric acid, which is the limiting reactant?
AleksAgata [21]

Answer:

Hydrosulfuric acid will act as limiting reactant.

Explanation:

Given data:

Mass of iron(III) chloride = 3243.0 g

Mass of hydrosulfuric acid = 511.8 g

Limiting reactant = ?

Solution:

Chemical equation:

2FeCl₃ + 3H₂S       →       Fe₂S₃ + 6HCl

Number of moles of iron(III) chloride:

Number of moles = mass/molar mass

Number of moles = 3243.0 g/ 162.2 g/mol

Number of moles = 20 mol

Number of moles of hydrosulfuric acid:

Number of moles = mass/molar mass

Number of moles = 511.8 g/ 34.1 g/mol

Number of moles = 15 mol

Now we will compare the moles of both reactant with products

                      FeCl₃          :          Fe₂S₃

                       2                :            1

                      20               :          1/2 ×20 = 10

                      FeCl₃          :            HCl

                       2                :              6

                      20               :          6/2 ×20 = 60

                      H₂S             :          Fe₂S₃

                       3                :            1

                      15               :          1/3 ×15 = 5

                      H₂S            :            HCl

                       3                :              6

                      15                :          6/3 ×15 = 30

Hydrosulfuric acid producing less number of moles of product thus, it will act as limiting reactant.

 

5 0
3 years ago
What are the products in a chemical reaction?
Natalka [10]

Answer:

it's c trust me

Explanation:

c cause it's c

6 0
3 years ago
Can i get a snap i could send a link to, to do a few chem 1 assignments i could award more points
Colt1911 [192]

Answer:The FitnessGram PACER Test is a multistage aerobic capacity test that progressively gets more difficult as it continues. The test is used to measure a student's aerobic capacity as part of the FitnessGram assessment. Students run back and forth as many times as they can, each lap signaled by a beep sound.

Explanation:

4 0
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