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Ksivusya [100]
3 years ago
8

Pleaseeeeeefgghhbbbbbbbbbb

Chemistry
1 answer:
ehidna [41]3 years ago
5 0
<h2>Hey There!</h2><h2>_____________________________________</h2><h2>Answer:</h2><h2>----------------------------------------------------------------------</h2><h2>ELECTROPLATING </h2>

Electroplating the plating one metal on to the another metal, It is mostly used for preventing corrosion by using copper or chromium or decorate the object by using gold or silver plating.

__________________________________________________________

<h3>Principle:</h3>

When electricity is passed the thin layer of metal is deposited on another metal and water molecule given out as a By-Product, Thus this process works on the principle of Hydrolysis.

<h2>_____________________________________</h2><h2>QUESTION:</h2>

A) Electrolysis

B) Chromium prevents corrosion and gives the fine shining touch to the objects.

C) The metal which is deposited to the object i.e. spoon will be connected to the positive electrode of a battery, Thus it is anode. The spoon at which electroplating is need to be done is connected to the negative electrode, thus the Spoon is cathode.

<h2>_____________________________________</h2><h2>Best Regards,</h2><h2>'Borz'</h2>

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I'm pretty sure the answer would be that the metal is conductive, which travels through the copper wires.

7 0
3 years ago
A chemist dissolves 248mg of pure hydrochloric acid in enough water to make up 140mL of solution.Calculate the pH of the solutio
evablogger [386]

Answer : The pH of the solution is, 1.31

Explanation : Given,

Mass of HCl = 248 mg = 0.248 g      (1 mg = 0.001 g)

Volume of solution = 140 mL

Molar mass of HCl = 36.5 g/mole

First we have to calculate the concentration of hydrochloric acid.

Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.

Formula used :

\text{Molarity}=\frac{\text{Mass of }HCl\times 1000}{\text{Molar mass of }HCl\times \text{Volume of solution (in mL)}}

Now put all the given values in this formula, we get:

\text{Molarity}=\frac{0.248g\times 1000}{36.5g/mole\times 140mL}=0.0485mole/L=0.0485M

The concentration of HCl is, 0.0485 M

As we know that, HCl dissociates to give hydrogen ion and chloride ion.

The dissociation reaction is:

HCl\rightarrow H^++Cl^-

Concentration of HCl = Concentration of H⁺ = Concentration of Cl⁻ = 0.0485 M

Now we have to calculate the pH of the solution.

pH : It is defined as the negative logarithm of hydrogen ion concentration.

Mathematically,

pH=-\log [H^+]

pH=-\log (0.0485)

pH=1.31

Therefore, the pH of the solution is, 1.31

6 0
3 years ago
How many metres further would the sound intensity be 1/2 times as much as that at a distance of 3 m from an acoustic source?
marshall27 [118]

Solution :

Let, intensity at distance 3 m from the acoustic source is I_o.

We need to find the distance d where the intensity is \dfrac{I_o}{2}.

Now, we know intensity is inversely proportional to square of distance between the source.

\dfrac{I_o}{\dfrac{I_o}{2}} = \dfrac{d^2}{3^2}\\\\d^2 = 18 \\\\d = 3\sqrt{2}\ m

Therefore, intensity will be halved at a distance of 3\sqrt{2}\ m.

7 0
2 years ago
Consider an AB3 molecule in which A and B differ in elec-tronegativity. You are told that the molecule has an over-all dipole mo
Alborosie

Answer:

(b) Trigonal planar

Explanation:

The molecular geometry is the one that stabilizes better the bonds and the free electron pairs. If the molecule is nonpolar (overall dipole moment zero), so, there's no free electron pairs at the central atom. So, the molecule has the central atom A surrounded by three atoms of B, which is the trigonal planar geometry.

5 0
3 years ago
Which three elements have lower melting point than calcium?
lakkis [162]

Calcium belongs to the alkaline earth metal group. Within a group, the melting point decreases from top to bottom. This is because the as the atomic radii increases the outer valence electrons are shielded by the inner electrons and experience a lower nuclear attraction. As a result the bonds can be broken easily which lowers their melting point.

The three elements below Calcium ib Group II A which have a lower melting point are: Strontium (Sr), Barium (Ba) and Radium (Ra)

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