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Tems11 [23]
3 years ago
12

What is a lone pair​

Chemistry
2 answers:
dolphi86 [110]3 years ago
8 0

Answer:

A lone pair is a pair of electrons occupying an orbital in an atom or molecule and not directly involved in bonding.

Explanation:

beks73 [17]3 years ago
3 0

Answer:

A pair of electrons that is not used in bonding

Explanation:

I took the test

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1. By means of orbital diagrams, write down the
Dvinal [7]

Answer:

a) 1s22s22p63s1

b) 3s² 3p¹

c) 1s22s22p63s23p3

d) 3s² 3p⁵

e) 3s2

f) 1s22s22p63s23p2

g) 1s22s22p63s23p4

h) 3s² 3p⁶

3 0
3 years ago
Which of these is a benefit of including comments in your code
morpeh [17]

A benefit of including comments in your code is that it helps other programmers understand your code.

<h3>What is a Code?</h3>

These are numbers and letters which are used to identify a particular thing at a point in  time.

Comments can be put in a code so as to enable others know and understand real intentions about it etc.

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3 0
3 years ago
Identify one disadvantage to each of the following models of electron configuration:
Murrr4er [49]

Answer:

The disadvantages of each of the given model of electron configuration have been mentioned below:

1). Dot Structures - They take up excess space as they do not display the electron distribution in orbitals.

2). Arrow and line diagrams make the counting of electrons and take up too much space.

3). Written Configurations do not display the electron distribution in orbitals and help in lose counting of electrons easily.

6 0
3 years ago
Read 2 more answers
How do you find the IUPAC name for a compound like ZnO
Elden [556K]
To find the IUPAC name for compounds, you must memorize prefixes and suffixes and other terms in determining or naming a compound. The IUPAC name for compound ZnO is Oxozinc or Zinc Oxide. I hope this helps you on your assignment.
6 0
4 years ago
In which of the following species does sulfur have the same oxidation number as it does in H2SO4?(A) H2SO3
Dmitry_Shevchenko [17]

Answer:

E

Explanation:

To solve this question, we need to know the oxidation number in the compound in the question. The name of the compound is tetraoxosulphate(vi) acid. We can obviously see that the oxidation number of sulphur in this particular compound is 6.

A. Is wrong

The name of the compound is trioxosulphate(iv) ion

B. Is wrong

S2O32-

2S + 3(-2) = -2

S = +2

C.is wrong

Oxidation state there is -2

D is wrong

The oxidation number here is zero

E is correct

Oxidation number of oxygen is -2 and that of chlorine is -1

Hence:

S + 2(-2) + 2(-1) = 0

S -4 -2 = 0

S = 4+2 = +6

6 0
4 years ago
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