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Tems11 [23]
3 years ago
12

What is a lone pair​

Chemistry
2 answers:
dolphi86 [110]3 years ago
8 0

Answer:

A lone pair is a pair of electrons occupying an orbital in an atom or molecule and not directly involved in bonding.

Explanation:

beks73 [17]3 years ago
3 0

Answer:

A pair of electrons that is not used in bonding

Explanation:

I took the test

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Substances have more kinetic energy in the _______ state than in the _______ state.
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Substances have more kinetic energy in the gas state than in the Solid state.

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What is 0.738 × 104? Enter your answer in the box.<br> _____
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In which case would recalibrating a thermometer be an important next step in an experiment dealing with boiling points?
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7 0
3 years ago
There are two steps in the usual industrial preparation of acrylic acid, the immediate precursor of several useful plastics. In
adell [148]

Answer:

The net change in enthalpy for the formation of one mole of acrylic acid from calcium carbide, water and carbon dioxide is 523.2 kJ.

Explanation:

Step 1:

CaC_2(s) + 2H_2O(g)\rightarrow C_2H_2(g) + Ca(OH)_2(s),\Delta H_1=414.0 kJ...[1]

Step 2 :

6C_2H_2(g) + 3CO_2(g) + 4H_2O(g)\rightarrow 5CH_2CHCO_2H(g) \Delta H_2=132.0kJ..[2]

Adding 6 × [1] and [2]:

6CaC_2(s) + 12H_2O(g)\rightarrow 6C_2H_2(g) + 6Ca(OH)_2(s)

6C_2H_2(g)+3CO_2(g)+16H_2O(g)\rightarrow 5CH_2CHCO_2H(g)

we get :

6CaC_2(s) + 8H_2O(g)+3CO_2(g)\rightarrow 5CH_2CHCO_2H(g)+ 6Ca(OH)_2(s),\Delta H'=?

\Delta H'=6\times \Delta H_1+\Delta H_2

\Delta H'=6\times 414.0 kJ+132.0kJ

\Delta H'=2,626 kJ

Energy released on formation of 5 moles of acrylic acid = 2,626 kJ

Energy released on formation of 1 mole of acrylic acid:

\frac{ 2,626 kJ}{5 } = 523.2 kJ

7 0
4 years ago
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