Answer:
The precipitate is CuS.
Sulfide will precipitate at [S2-]= 3.61*10^-35 M
Explanation:
<u>Step 1: </u>Data given
The solution contains 0.036 M Cu2+ and 0.044 M Fe2+
Ksp (CuS) = 1.3 × 10-36
Ksp (FeS) = 6.3 × 10-18
Step 2: Calculate precipitate
CuS → Cu^2+ + S^2- Ksp= 1.3*10^-36
FeS → Fe^2+ + S^2- Ksp= 6.3*10^-18
Calculate the minimum of amount needed to form precipitates:
Q=Ksp
<u>For copper</u> we have: Ksp=[Cu2+]*[S2-]
Ksp (CuS) = 1.3*10^-36 = 0.036M *[S2-]
[S2-]= 3.61*10^-35 M
<u>For Iron</u> we have: Ksp=[Fe2+]*[S2-]
Ksp(FeS) = 6.3*10^-18 = 0.044M*[S2-]
[S2-]= 1.43*10^-16 M
CuS will form precipitates before FeS., because only 3.61*10^-35 M Sulfur Ions are needed for CuS. For FeS we need 1.43*10^-16 M Sulfur Ions which is much larger.
The precipitate is CuS.
Sulfide will precipitate at [S2-]= 3.61*10^-35 M
Answer:
it is heterotrophic. it is unicellular. it does not have a nucleus.
Explanation:
Answer:
There are 5.43 grams of NaOCl
Explanation:
The given percent by mass of the solute tells us that out of the 150 g of the solution, 3.62% are due solely to the solute.
In other words, <u>the mass of the solute in the solution is</u>:
- 150 g * 3.62/100 = 5.43 g
Thus, in 150 grams of the given bleach solution, there are 5.43 grams of sodium hypochlorite.
C) volume
.........
The volume of gas depends on e.g. temperature and pressure.
Concentration and ion moles are equal only when volume is 1. Of 1.0 x 10-6 and 1.0 x 10-4, the larger number is 1.