1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Readme [11.4K]
3 years ago
14

A baseball weighs 220 g. Top speed for a professional pitcher is about 100 mph when he throws a fast ball. Find the de Broglie w

avelength (in nm) associated with a baseball that is moving with a velocity of 42 mph
Chemistry
1 answer:
Alexeev081 [22]3 years ago
6 0

Answer:

1.604\times 10^{-25} nm is the de Broglie wavelength associated with a baseball that is moving with a velocity of 42 mph.

Explanation:

De-Broglie's wavelength, which is:

\lambda=\frac{h}{mv}

where,

\lambda = De-Broglie's wavelength = ?

h = Planck's constant = 6.626\times 10^{-34}Js

m = mass of particle  =

v = velocity of the particle

We have :

Mass of baseball = m = 220 g = 0.220 kg ( 1g = 0.001 kg)

Velocity of the base ball = v = 42mph =\frac{42}{2.237} m/s=18.78 m/s

1 m/s = 2.237 mph

De-Broglie wavelength of the baseball at v:\lambda

\lambda =\frac{6.626\times 10^{-34}Js}{0.220 kg\times 18.78 m/s}=1.604\times 10^{-34} m=1.604\times 10^{-25} nm[/tex]

1 m = 10^9 nm

1.604\times 10^{-25} nm is the de Broglie wavelength associated with a baseball that is moving with a velocity of 42 mph.

You might be interested in
Use the periodic table entry below to answer the following question.
Komok [63]
The answer is 59
the atomic mass is the number at the bottom so you've gotta round it to the nearest whole number<span />
6 0
3 years ago
The method by which the substances in a mixture are separated is called what?
yanalaym [24]

Answer:

Filtration is a separation method used to separate out pure substances in mixtures comprised of particles some of which are large enough in size to be captured with a porous material.

8 0
3 years ago
Pls help lollollolljdjdjdjdjjdjjzjzjsjsjsis
HACTEHA [7]

Answer:

djhdhdjdududddhhrhed

3 0
3 years ago
You could add aquous hydrochloric to the solution to precipitate out silver chloride. What volume of a 0.130 M aqueous hydrochlo
Mila [183]
1) Chemical reaction: AgNO₃ + HCl → AgCl + HNO₃.
V(AgNO₃) = 30,0 mL = 0,03 L.
c(AgNO₃) = 0,225 mol/L.
n(AgNO₃) = 0,03 L · 0,225 mol/L.
n(AgNO₃) = 0,00675 mol.
From chemical reaction: n(AgNO₃) : n(HCl) = 1 : 1.
0,00675 mol : n(HCl) = 1 : 1.
n(HCl) = 0,00675 mol.
V(HCl) = n(HCl) ÷ c(HCl).
V(HCl) = 0,00675 mol ÷ 0,130 mol/L.
V(HCl) = 0,0519 L = 51,92 ml.

2) 1) Chemical reaction: AgNO₃ + KCl → AgCl + KNO₃.
V(AgNO₃) = 30,0 mL = 0,03 L.
c(AgNO₃) = 0,225 mol/L.
n(AgNO₃) = 0,03 L · 0,225 mol/L.
n(AgNO₃) = 0,00675 mol.
From chemical reaction: n(AgNO₃) : n(KCl) = 1 : 1.
0,00675 mol : n(KCl) = 1 : 1.
n(KCl) = 0,00675 mol.
m(KCl) = n(KCl) · M(KCl).
m(KCl) = 0,00675 mol · 74,55 g/mol.
m(KCl) = 0,503 g.
n - amount of substance.
M - molar mass.
5 0
3 years ago
Air containing 0.04% carbon dioxide is pumped into a room whose volume is 6000 ft3. The air is pumped in at a rate of 2000 ft3/m
koban [17]

Here is the full question:

Air containing 0.04% carbon dioxide is pumped into a room whose volume is 6000 ft3. The air is pumped in at a rate of 2000 ft3/min, and the circulated air is then pumped out at the same rate. If there is an initial concentration of 0.2% carbon dioxide, determine the subsequent amount in the room at any time.

What is the concentration at 10 minutes? (Round your answer to three decimal places.

Answer:

0.046 %

Explanation:

The rate-in;

R_{in} = \frac{0.04}{100}*2000

R_{in} = 0.8

The rate-out

R_{out} = \frac{A}{6000}*2000

R_{out} = \frac{A}{3}

We can say that:

\frac{dA}{dt}= 0.8-\frac{A}{3}

where;

A(0)= 0.2% × 6000

A(0)= 0.002 × 6000

A(0)= 12

\frac{dA}{dt} +\frac{A}{3} =0.8

Integration of the above linear equation =

e^{\int\limits \frac {1}{3}dt } = e^{\frac{1}{3}t

so we have:

e^{\frac{1}{3}t}\frac{dA}{dt}} +\frac{1}{3}e^{\frac{1}{3}t}A = 0.8e^{\frac{1}{3}t

\frac{d}{dt}[e^{\frac{1}{3}t}A] = 0.8e^{\frac{1}{3}t

Ae^{\frac{1}{3}t} =2.4e\frac{1}{3}t +C

∴ A(t) = 2.4 +Ce^{-\frac{1}{3}t

Since A(0) = 12

Then;

12 =2.4 + Ce^{-\frac{1}{3}}(0)

C= 12-2.4

C =9.6

Hence;

A(t) = 2.4 +9.6e^{-\frac{t}{3}}

A(0) = 2.4 +9.6e^{-\frac{10}{3}}

A(t) = 2.74

∴ the concentration at 10 minutes is ;

=  \frac{2.74}{6000}*100%

= 0.0456667 %

= 0.046% to three decimal places

7 0
4 years ago
Other questions:
  • Evidence shows that interstellar bodies are moving away from Earth, some faster than others, which BEST suggests that the univer
    15·2 answers
  • Why is a solution of naoh which was standardized yesterday unsuitable to be used as a standard solution today?
    13·1 answer
  • Which of the following is not a property of an acid?
    13·2 answers
  • Which elements are represented by the symbols S and Na?
    9·1 answer
  • The composition of a compound is 20.01% carbon and 79.99% oxygen by mass. what is its empirical formula?
    15·1 answer
  • Help me out anybody plz
    10·2 answers
  • How much precipitation does the tundra get?
    11·1 answer
  • PlzzzHelp help help plz
    7·2 answers
  • What happens to the actin and myosin during a muscle contraction
    13·1 answer
  • What is the right ratio of chemicals for the BCE (Balanced Chemical Equation)?
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!