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Bingel [31]
3 years ago
11

If a 60 kg dog is on a 15 kg sled is pushed with a force of 300 N, what will be dogs acceleration? A) 900 N B) 4 kg C) 4 m/s2 D)

0.25 m/s2
Chemistry
2 answers:
Mamont248 [21]3 years ago
7 0
The answer is C, because 60 divided by 15 is 4.
Hope this Helps!
Mark me Brainliest, Please
stepan [7]3 years ago
6 0
The answer is C because you have to find acceleration.
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Answer:

FeCl3(aq) -

3NaOH(aq) 0 Fe(OH)3(s) -

3NaCl(aq)

Explanation:

FeCl3(aq) -

3NaOH(aq) 0 Fe(OH)3(s) -

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7 0
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A sample of Manganese (II) chloride has a mass of 19.8 grams before heating, and 12.6 grams after heating until all the water is
IRINA_888 [86]

Answer:

no. of water molecules associated to each molecule of MnCl_2 = 4

Explanation:

Mass of MnCl_2 before heating = 19.8 g

Mass of MnCl_2 after heating = 12.6 g

Difference in mass of MnCl_2 before and after heating

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Difference in mass corresponds to mass of water driven out.

Molar mass of water = 18 g/mol

No. of moles of water = \frac{7.2}{18} = 0.4\ mol

Mass of MnCl_2 obtained after heating is mass of anhydrous MnCl_2.

Mass of anhydrous MnCl_2 = 12.6 g

Molar mass of MnCl_2 = 125.9 g/mol

No. of mol of anhydrous MnCl_2 = \frac{125.9}{125.9} = 0.1\ mol

so,

0.1 mol of MnCl_2 have 0.4 mol of water

1 mol of MnCl_2 will have = \frac{0.4}{0.1} =4\ mol

Hence, no. of water molecules associated to each molecule of MnCl_2 = 4

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3 years ago
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Leviafan [203]
The formula would be MgMn2O8
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sukhopar [10]

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babunello [35]

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3 years ago
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