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Bingel [31]
3 years ago
11

If a 60 kg dog is on a 15 kg sled is pushed with a force of 300 N, what will be dogs acceleration? A) 900 N B) 4 kg C) 4 m/s2 D)

0.25 m/s2
Chemistry
2 answers:
Mamont248 [21]3 years ago
7 0
The answer is C, because 60 divided by 15 is 4.
Hope this Helps!
Mark me Brainliest, Please
stepan [7]3 years ago
6 0
The answer is C because you have to find acceleration.
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f a solution containing 85.14 g of mercury(II) nitrate is allowed to react completely with a solution containing 14.334 g of sod
Phantasy [73]
  • <u>The reaction that takes place is:</u>

Hg(NO₃)₂(ac) + Na₂S(ac) → HgS(s) + 2Na⁺ + 2NO₃⁻

Now we calculate the moles of each reagent -using the molecular weights-, in order to determine the limiting reactant:

  • Moles of mercury (II) nitrate = 85.14 g * \frac{1mol}{324.7g}=0.2622 moles.
  • Moles of sodium sulfide = 14.334 g *\frac{1mol}{78.04g}=0.1837 moles.

Because the stoichiometric ratio between the reactants is 1:1, we compare the number of moles of each one upfront.

moles Hg(NO₃)₂ > moles Na₂S

<u>Thus Na₂S is the limiting reagent.</u>

So in order to find the mass of solid precipitate, we must calculate it using the moles of Na₂S:

0.1837 molNa_{2} S*\frac{1molHgS }{1molNa_{2}S}*\frac{232.66g}{1molHgS} =42.740g

The mass of the solid precipitate is 42.760 g.

  • In order to calculate the grams of the reactant in excess that will remain after the reaction, we convert the moles that reacted into mass and substract them from the original mass:

Mass of Hg(NO₃)₂ remaining = 85.14g-(0.1837molHg(NO_{3})_{2} * 324.7 g/mol)=25.49g

The mass of the remaning reactant in excess is 25.49 g.

  • Because we assume complete precipitation, there are no more Hg⁺² or S⁻² ions in solution. The moles of NO₃⁻ and Na⁺ in solution remain the same during the reaction, so the number is calculated from the number added in the reactant:

Hg⁺²: 0 mol

NO₃⁻: 0.2622molHg(NO_{3})_{2} *\frac{2molNO_{3}^{-}}{1molHg(NO_{3})_{2} *} =0.5244molNO_{3}^{-}

Na⁺: 0.1837molNa_{2} S*\frac{1molNa^{+}}{1molNa_{2}}=0.1837molNa^{+}

S²⁻: 0 mol

6 0
3 years ago
Determine the concentration of sulfuric acid that needed 47 mL of 0.39M potassium hydroxide solution to neutralize a 25 mL sampl
77julia77 [94]

Answer:

<u></u>

  • <u>0.37M</u>

Explanation:

Since sulfuric acid, H₂SO₄, is a diprotic acid and potassum hydroxide, KOH, contains one OH⁻ in the formula, the number of moles of potassium hydroxide must be twice the number of moles of sulfuric acid.

<u>1. Determine the number of moles of KOH in 47mL of 0.39M potassium hydroxide solution</u>

  • number of moles = molarity × volume in liters
  • number of moles = 0.39M × 47mL × 1liter/1,000 mL = 0.1833mol

<u>2. Determine the number of moles of sulfuric acid needed</u>

  • number of moles of H₂SO₄ = number of moles of KOH/2 = 0.1833/2 = 0.009165mol

<u>3. Determine the concentration that contains 0.009165 mol in 25mL of the acid.</u>

  • Molarity = number of moles / volume in liters
  • M = 0.009165mol/(25mL) × (1,000mL/liter) = 0.3666M

Round to two significant figures: 0.37M

7 0
3 years ago
Science always begins with what?
tiny-mole [99]

Step 7- Communicate. Present/share your results. Replicate.

Step 1- Question.

Step 2-Research.

Step 3-Hypothesis.

Step 4-Experiment.

Step 5-Observations.

Step 6-Results/Conclusion.

3 0
3 years ago
How much energy (heat) is required to convert 52.0 g of ice at –10.0°C to steam at 100°C? Specific heat of ice 2.09 J/g • °C Spe
dexar [7]

Answer: The energy (heat) required to convert 52.0 g of ice at –10.0°C to steam at 100°C is 157.8 kJ

Explanation:

Using this formular, q = [mCpΔT] and = [nΔHfusion]

The energy that is needed in the different physical changes is thus:

The heat needed to raise the ice temperature from -10.0°C to 0°C is given as as:

q = [mCpΔT]

q = 52.0 x 2.09 x 10

q = 1.09 kJ

While from 0°C to 100°C is calculated as:

q = [mCpΔT]

q = 52.0 x 4.18 x 100

q = 21.74 kJ

And for fusion at 0°C is called Heat of fusion and would be given as:

q = n ΔHfusion

q = 52.0 / 18.02 x 6.02

q = 17.38 kJ

And that required for vaporization at 100°C is called Heat of vaporization and it's given as:

q = n ΔHvaporization

q = 52.0 / 18.02 x 40.7

q = 117.45 kJ

Add up all the energy gives 157.8 kJ

5 0
3 years ago
Why is it important to control the reaction rate of the chemical process
xxTIMURxx [149]
Mg+2HCl=MgCl_2+H_{2(g)}

The reaction creates dihydrogen, hence if it's uncontrolled it could lead to potentially dangerous amounts of gas being released at once.
8 0
3 years ago
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