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3 years ago

An object's describes it's distance and direction from a reference point .

Physics

2 answers:

Ainat [17]3 years ago

4 0

6: velocity i hpe this is what your looking for

7nadin3 [17]3 years ago

3 0

The answer is 4: position.

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A 1000kg car is rolling slowly across a level surface at 1 m/s heading twoards a group o fsmall innocent children. The doors are

Degger [83]

Answer:

The force required to push to stop the car is 288.67 N

Explanation:

Given that

Mass of the car, m = 1000 kg

Initial speed of the car, u = 1 m/s

The car and push on the hood at an angle of 30° below horizontal, $\theta=30^{\circ}$

Distance, d = 2 m

Let F is the force must you push to stop the car.

According work energy theorem theorem, the work done is equal to the change in kinetic energy as :

$W=\dfrac{1}{2}m(v^2-u^2)F\times d=\dfrac{1}{2}m(v^2-u^2)$

$v = 0$

$Fd\ cos\theta=\dfrac{1}{2}m(u^2) F=\dfrac{\dfrac{1}{2}m(u^2)}{d\ cos\theta}F=\dfrac{\dfrac{1}{2}\times 1000\times (1)^2}{2\ cos(30)}F = -288.67 N$

The force required to push to stop the car is 288.67 N

3 0

3 years ago

Solve for M₂

soldi70 [24.7K]

Explanation:

M₂ = Fr²/GM₁

M₂ = [(132N)(.243m)²]/[(6.67*10^-11N*m²/kg)(1.175*10^4kg)]

M₂ = (7.79N*m²)/(7.84*10^-7N*m²)

M₂ = 9.94*10^6 kg

5 0

3 years ago

A car travels 45 km due north and 70 km west. What is the car's displacement?

Elis [28]

Answer:

Explanation:

7 0

3 years ago

The volume and the mass of substance are 15cm3 and 27 gm respectively find its density

harina [27]

Answer:

$d=1.8\ g/cm^3$

Explanation:

Given that,

Mass, m = 27 grams

Volume of the substance, V = 15 cm³

We need to find the density of the substance. We know that, the density of an object is given by mass per unit volume. So,

$d=\dfrac{m}{V}\\\\d=\dfrac{27}{15}\\\\d=1.8\ g/cm^3$

So, the density of the substance is equal to $1.8\ g/cm^3$ .

8 0

3 years ago

Calculen si a nivel del mar se reciben del sol 1000 watts por metro cuadrado y un panel solar genera 200 watts, ¿Cuál es la dife

bogdanovich [222]

Answer:

Diferencia de energía de las dos fuentes = 800 watts

Explanation:

Cantidad de energía recibida en el mar = 1000

Cantidad de energía solar recibida en el mar = 200

Diferencia de energía de las dos fuentes = 1000 -200 = 800 watts

7 0

2 years ago