Answer:
Cytoplasm.
Explanation:
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1 atom Mg, 2 atoms O and 2 atoms H.
1 + 2 + 2 = 5, so correct answer is C
Answer: has zero mass
is an electron
has a -1 charge
is electromagnetic energy
Explanation:
A beta-particle is an electron emitted from the nucleus of an atom following the decay of a neutron into a proton. Beta rays are deflected by a magnetic field in a direction that indicates a negative charge, thus they are electromagnetic in nature.
The beta particle released is basically a electron with -1 charge and no mass.
General representation of beta particle in the form of 
given as 
where,
Z represents Atomic number
A represents Mass number
X represents the symbol of an element
Note: The question is incomplete. The complete question is given below :
Suppose a substance has a heat of fusion equal to 45 cal/g and a specific heat of 0.75 cal/g°C in the liquid state. If 5.0 kcal of heat are applied to a 50 g sample of the substance at a temperature of 24°C, what will its new temperate be? What state will the sample be in? (melting point of the substance = 27°C; specific heat of the solid =0.48 cal/g°C; boiling point of the substance = 700°C)
Explanation:
1.a) Heat energy required to raise the temperature of the substance to its melting point, H = mcΔT
Mass of solid sample = 50 g; specific heat of solid = 0.75 cal/g; ΔT = 27 - 24 = 3 °C
H = 50 × 0.75 × 3 = 112.5 calories
b) Heat energy required to convert the solid to liquid at its melting point at 27°C, H = m×l, where l = 45 cal/g
H = 50 × 45 = 2250 cal
c) Total energy used so far = 112.5 cal + 2250 cal = 2362.5 calories.
Amount of energy left = 5000 - 2362.5 = 2637.5 cal
The remaining energy is used to heat the liquid
H = mcΔT
Where specific heat of the liquid, c = 0.75 cal/g/°C, H = 2637.5 cal, ΔT = temperature change
2637.5 = 50 × 0.75 x ΔT
ΔT = 2637.5 / ( 50*0.75)
ΔT = 70.3 °C
Final temperature of sample = (70.3 + 27) °C = 97.3 °C
The substance will be in liquid state at a temperature of 97.3 °C
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A formula unit of the nitrate salt of Q is Q(NO3)2.
<h3>What is IUPAC nomenclature?</h3>
The IUPAC nomenclature was put together by the international Union of Pure and applied chemistry in order to have a uniform way of naming compounds.
We shall now find the names of the compounds;
1) Na* and HPO4²- ; sodium hydrogen tetraoxophoshate V
2) Potassium cation and cyanide anion ; Potassium cyanide
3) Calcium cation and hypochlorite anion; Calcium oxochlorate I
Knowing that the valency of NO3^- is one and that the compound formed between Q and CO3²- has the formula QCO3 we can conclude that a formula unit of its nitrate salt is Q(NO3)2.
Learn more about IUPAC nomenclature:brainly.com/question/14379357
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