<span>Hess' Law states that the enthalpy change in a reaction can be calculated from the enthalpy changes of reactions that, when combined, result in the desired reaction.
For example, to check the enthalpy change that occurs when benzene undergoes incomplete combustion to water and carbon monoxide is not an easy task, because the products invariably contain CO2. However, by combining the reactions of the complete combustion of benzene and the combustion of CO, you can get the reaction you want.
Reaction wanted: 2C6H6 + 9O2 → 12CO + 6H2O
Reactions provided: 2C6H6 + 15O2 → 12CO2 + 6H2O and 2CO + O2 → 2CO2, and their associated ΔH.
Rearrange the reactions so that, when they add up, they result in the wanted reaction.
2C6H6 + 15O2 → 12CO2 + 6H2O (leave as is; no changes to ΔH)
12CO2 → 12CO + 6O2 (reverse and multiply by 6; this changes the sign of ΔH and multiplies it by 6)
Added up, it will result in 2C6H6 + 9O2 → 12CO + 6H2O. Add up the ΔH values for the rearranged reactions to find ΔH for this particular reaction.</span>
A.
Explain: I think this….
Iconic compounds are electrolytes because they dissociate into ions when dissolved in water. Many molecules compounds are noneelectrolytes
Answer: 2.54g
Explanation:
Molar Mass of H2O2 = (2x1) + (2x16) = 34g/mol
1mole (34g) of H2O2 contains 6.02x10^23 molecules
Therefore Xg of H2O2 will contain 4.5x10^22 molecules i.e
Xg of H2O2 = (34x4.5x10^22)/6.02x10^23 = 2.54g
<span>The reaction rate increases.
Why </span><span>Well a catalyst usually lower the activation barrier in an energy diagram. The lower and smaller that gap means the reaction is taking place rapidly compared to when that activation barrier gap is higher. </span>
