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3 years ago

The chemical energy in your food is

Physics

1 answer:

ale4655 [162]3 years ago

8 0

Answer:

Electromanetic

Explanation:ESPERO TE AYUDE

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When an object is at a distance of twice the focal length from a concave lens, the image produced is virtual and smaller than th

Elenna [48]

The right answer for the question that is being asked and shown above is that: "The image produced is virtual and of the same size as the object." the image if the object is shifted closer to the lens to a point one focal length away from it is that The image produced is virtual and of the same size as the object.<span>
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3 years ago

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At a rock concert, the sound intensity 1.0 m in front of the bank of loudspeakers is 0.10 W/m2. A fan is 30 m from the loudspeak

aliina [53]

Explanation:

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5 0

3 years ago

During takeoff, an airplane climbs with a speed of 195 m/s at an angle of 15° above the horizontal. The speed and angle constitu

matrenka [14]

Answer:

The horizontal component of the velocity is 188 m/s

The vertical component of the velocity is 50 m/s.

Explanation:

Hi there!

Please, see the figure for a graphic description of the problem. Notice that the x-component of the vector velocity (vx), the y-component (vy) and the vector velocity form a right triangle. Then, we can use trigonometry to obtain the magnitude of vx and vy:

We can find vx using the following trigonometric rule of a right triangle:

cos α = adjacent / hypotenuse

cos 15° = vx / 195 m/s

195 m/s · cos 15° = vx

vx = 188 m/s

The horizontal component of the velocity is 188 m/s

To calculate the y-component we will use the following trigonometric rule:

sin α = opposite / hypotenuse

sin 15° = vy / 195 m/s

195 m/s · sin 15° = vy

vy = 50 m/s

The vertical component of the velocity is 50 m/s.

4 0

3 years ago

A fuse in an electric circuit is a wire that is designed to melt, and thereby open the circuit, if the current exceeds a predete

zmey [24]

Answer:

The diameter of wire should be $4.04 \times 10^{-4}$ m

Explanation:

Given:

Current density $J = 500 \times 10^{4}$ $\frac{A}{m^{2} }$

Current $I = 0.64$ A

From the formula of current density,

$J = \frac{I}{A}$

Where $A =$ area of cylindrical wire = $\pi r^{2}$

$\pi r^{2} = \frac{I}{J}$

$r^{2} = \frac{I}{\pi J }$

$r = \sqrt{\frac{0.64}{3.14 \times 500 \times 10^{4} } }$

$r = 2.02 \times 10^{-4}$ m

For finding the diameter of wire,

$d = 2r$

$d = 4.04 \times 10^{-4}$ m

Therefore, the diameter of wire should be $4.04 \times 10^{-4}$ m

8 0

3 years ago

Cables and conductors installed on the side of a pole or building shall be protected up to ___feet above finished grade.

Allisa [31]

Answer:

10 feet.

Explanation:

Conductors are considered outside the building when they installed. The requirement of NEC is above 10 feet for the clearance after the final grade for service conductors and cables where they are connected with the building, above the sidewalks and the to other areas which are accessible to the pedestrians.

8 0

3 years ago