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Ivanshal [37]
3 years ago
9

Why are chemical changes considered "unseen"

Physics
1 answer:
morpeh [17]3 years ago
4 0
Because they occur at an atomic level, changing the actual structure of the thing.
Hope it helps
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Why is oxygen more chemically reactive than nitrogen?
grin007 [14]

Answer:

O2 has two more electrons compared to N2, with extra 2 electrons in the higher energy anti-bonding orbitals known as Diradical. These electrons have higher energy and are unpaired; therefore, O2 is more reactive

Explanation:

5 0
3 years ago
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When you go camping, you burn wood. Are you contributing to air pollution?
Jet001 [13]
Yes because of the smoke you are creating in the air
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James rode his bike 0.65 hours and traveled 8.45 km. What was his speed?
maria [59]

Speed = (distance covered) / (time to cover the distance)

            =    ( 8.45 km)   /   (0.65 hr)

            =         (8.45 / 0.65)  km/hr

            =                  13 km/hr
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3 years ago
An eccentric inventor attempts to levitate by first placing a large negative charge on himself and then putting a large positive
GuDViN [60]

Answer:

shirt is little attached to the body, it can come off and fly away

Explanation:

In electrostatics, charges of different signs attract and charges of the same sign repel.

In this case, when a negative charge is placed on it, both the inventor and the shirt are charged, therefore there is a repulsive force, also there is an attraction between the positive charge of the roof attracts the negative charge, such as the shirt. of weak the two forces not greater than the resistance of the walk.

As the shirt is little attached to the body, it can come off and fly away

3 0
3 years ago
A circuit has a current of 2.4 A. The voltage is increased to 4 times its original value, while the resistance stays the same. H
9966 [12]

Answer:

Resistance will become 4 times the previous value

Explanation:

We have given current in the circuit i = 2.4 A

According to ohm's law current in the circuit is given by I=\frac{V}{R}

So 2.4=\frac{V}{R}............eqn 1

Now voltage is increased to 4 times so new voltage = 4 V

And current in the circuit is same as 2.4 A

We have to fond the resistance so that after increasing voltage current will be same

So 2.4=\frac{4V}{R_{unknown}}..........eqn 2

Dividing eqn 1 and 2

1=\frac{V}{R}\times \frac{R_{unkown}}{4V}

R_{unknown}=4R

So resistance will become 4 times the previous value

6 0
3 years ago
Read 2 more answers
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