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Anni [7]
2 years ago
11

When the acceleration of a mass on a spring is zero, the velocity is at a

Physics
1 answer:
Sergeu [11.5K]2 years ago
6 0

1) Maximum

2) Maximum

Explanation:

The force acting on a mass on a spring is given by Hooke's law; in magnitude:

F=kx

where

F is the force

k is the spring constant

x is the displacement

Also we know from Newton's second law that we can write

F=ma

where

m is the mass

a is the acceleration

So we can write the equation as

ma=kx (1)

From this relationship, we see that the acceleration is directly proportional to the displacement.

On the other hand, we know that the total mechanical energy of the system mass-spring is constant, and it is given by

E=\frac{1}{2}kx^2+\frac{1}{2}mv^2=const. (2)

where the first term is the elastic potential energy while the second term is the kinetic energy, and where

v is the velocity of the mass

From eq. (2), it is clear that when displacement increases, velocity decreases, and vice-versa; however, from eq.(1) we also know that acceleration is proportional to the displacement.

Therefore this means that:

- When acceleration increases, velocity decreases

- When acceleration decreases, velocity increases

Therefore, the two answers here are:

- When the acceleration of a mass on a spring is zero, the velocity is at a  maximum

When the velocity of a mass on a spring is zero, the acceleration is at a  maximum

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A 5.7 kg block attached to a spring executes simple harmonic motion on a frictionless horizontal surface. At time t = 0s, the bl
Genrish500 [490]

Answer:

Explanation:

Given

mass of block m=5.7\ kg

at t=0 s

displacement is x=-0.7\ m

velocity v=-0.8\ m/s

acceleration a=2.7\ m/s^2

suppose x=A\cos (\omega t+\phi )   is the general equation of SHM

where A=amplitude

\omega=natural frequency of oscillation

therefore velocity and acceleration is given by

v=-A\omega \sin (\omega t+\phi )

a=A\omega ^2\cos (\omega t+\phi )

for t=0

-0.7=A\cos (\phi )---1

v=-0.8=-A\omega \sin(\phi)---2

a=2.7=-A\omega ^2\cos(\phi )----3

divide 1 and 3 we get

\omega ^2=\frac{27}{7}

\omega =\sqrt{\frac{27}{7}}

Now square and 1 and 2 we get

(0.7)^2+(\frac{0.8}{\omega })^2=A^2

A^2=0.49+0.166

A=0.81\ m

     

3 0
3 years ago
(06.01 LC)
Alexandra [31]

Answer:

It remains the same.

Explanation:

During physical change, the mass, number of atoms and number of molecules will remain the same.

5 0
3 years ago
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If a 100-N net force acts on a 50-kg car, what will the acceleration of the car be?
Tema [17]
Newton's 2nd law of motion: 

                             Force = (mass) x (acceleration)

Divide each side by (mass):     

                             Acceleration = (force) / (mass)

                                               =  (100 N) / (50 kg)

                                               =  2 m/s²  


5 0
3 years ago
Can someone answer my last question you could get 25 points total​
enyata [817]

Answer:

Hi where is question. Hope you understand me

5 0
2 years ago
Determine which heat transfers below are due to the process of conduction. I) You walk barefoot on the hot street and it burns y
Rudik [331]

I) You walk barefoot on the hot street and it burns your toes.

The road is in direct contact with your skin. Thermal energy from the road will transfer to the bottom of your feet, then to the rest of your body. This is an example of conduction.


II) When you get into a car with hot black leather in the middle of the summer and your skin starts to get burned.

Just like in the previous example, the hot leather is in direct contact with your skin (I guess if you're going to drive naked). Thermal energy from the leather will transfe to your skin, then to the rest of your body. This is also conduction.


III) A flame heats the air inside a hot air balloon and the balloon rises.

The flame heats air directly at the bottom of the balloon. The warm air expands and becomes less dense. This will rise and let the unheated, denser air in the balloon fall down toward the flame. This is an example of the convection cycle.


IV) A boy sits to the side of a campfire. He is 10 feet away, but still feels warm.

The campfire heats air directly nearby. The warm air expands and moves away from the fire in all directions, leaving behind unheated, denser air to be heated up. Some of the warm air reaches the boy. This is another example of convection.


The answer is A) 1 and 2.

3 0
3 years ago
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