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jonny [76]
3 years ago
6

A car is traveling at a constant speed on the highway. Its tires have a diameter of 65.0 cm and are rolling without sliding or s

lipping. If the angular speed of the tires is 49.0 rad/s , what is the speed of the car, in SI units
Physics
1 answer:
lesya692 [45]3 years ago
4 0

Answer:

Explanation:

The car is rolling without slipping so Vcm= R×ω = 0.325×49 = 16

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At height h above the surface of Earth, the gravitational acceleration is What is h? Note: The radius of Earth is 6380 km.
rusak2 [61]

The acceleration of gravity is inversely proportional to
the square of the distance from Earth's center.

The acceleration of gravity is 9.8 m/s² on the Earth's surface ...
6380 km from the center.

If the acceleration of gravity at 'h' is 4.9 m/s² ... 1/2 of what it is
on the surface, then the distance from the center is

                 (6380 x √2) =  9,023 km  (rounded) ,

and 'h' is the distance above the surface

                     = (9,023 - 6,380) =  2,643 km  (rounded) .

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3 years ago
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melamori03 [73]

All three windows are the same size.

A has 10 complete waves visible through the window. B has 3, and C has 4.

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3 years ago
Read 2 more answers
Greg throws a 2.8-kg pumpkin horizontally off the top of the school roof in order to hit Mr. H's car. The car has parked a dista
Igoryamba

Answer:

The horizontal velocity is v = 9.2 m/s

Explanation:

From the question we are told that

     The mass of the pumpkin is  m = 2.8 \ kg

      The distance of the the car from the building's base is  d = 13.4 \ m

       The height of the roof is h = 10.4 \ m

       

The height is mathematically represented as

         h = \frac{1}{2} gt^2

Where g is the acceleration due to gravity which has a value of g =9.8 \ m/s^2

substituting values

          10.4= 0.5 * 9.8 * t

making the time taken the subject of the formula

         t = \frac{10.4}{0.5 * 9.8 }

          t = 1.457 \ s

The speed at which the pumpkin move horizontally can be represented mathematically  as

                         v = \frac{d}{t}

substituting values

                     v =\frac{13.4}{1.457}

                     v = 9.2 m/s

7 0
3 years ago
The strength of the force of friction depends on which two factors?
Stolb23 [73]

Options A and D are correct. The strength of the force of friction depends on the objects' sizes and weights and the heat generated by the friction and the types of surfaces involved.

<h3 /><h3>What is the friction force?</h3>

It is a type of opposition force acting on the surface of the body that tries to oppose the motion of the body. its unit is Newton (N).

Mathematically, it is defined as the product of the coefficient of friction and normal reaction.

On resolving the given force and acceleration in the different components and balancing the equation gets. Components in the x-direction.

The strength of the force of friction depends on the two factors, as;

A. The objects' sizes and weights.

D. The heat generated by the friction and the types of surfaces involved.

Hence, options A and D are correct.

To learn more about the friction force, refer to the link;

brainly.com/question/1714663

#SPJ1

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2 years ago
Which three factors are used to calculate gravitational potential energy?
Elis [28]

Explanation:

PEgrav = m *• g • h

In the above equation, m represents the mass of the object, h represents the height of the object and g represents the gravitational field strength (9.8 N/kg on Earth) - sometimes referred to as the acceleration of gravity.

www.physicsclassroom.com › energy

Potential Energy - The

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