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3 years ago

Which measurement can be made using a micrometer screw gauge?

Physics

1 answer:

insens350 [35]3 years ago

5 0

Answer:

C. The diameter of a wire

Explanation:

A micrometer screw gauge is a device used for the measurement of small dimensions which may not be measured accurately by the use of a vernier caliper, e.g diameter of a thin wire. it has a high degree of accuracy.

From the given option in the question, the measurement that can be made using a micrometer screw gauge is the diameter of a wire

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A 40 kg boy on a skateboard throws a 2 kg ball at 20 m/s to the left. How fast did the boy move to the right on his skateboard?

sergey [27]

According to my examination I have confirmed that I do NOT repeat do NOT know this .

4 0

3 years ago

A futuristic train rushes past you at an incredible, relativistic speed such that it appears to only be 80% as long as you know

Fed [463]

Answer:

v = 0.6c = 1.8 x 10⁸ m/s

Explanation:

From Einstein's theory of relativity, we know that the length of an object contracts while traveling at a speed relative to speed of light. The contraction is according to following equation:

$L = L_{0}\sqrt{1 - \frac{v^2}{c^2}}$

where,

L = Relative Length

L₀ = Rest Length

According to given:

L = 0.8 L₀

c = speed of light = 3 x 10⁸ m/s

v = relative speed of train = ?

Therefore,

$0.8L_{0} = L_{0}\sqrt{1 - \frac{v^2}{c^2} } \\\\0.8 = \sqrt{1 - \frac{v^2}{c^2} }$

squaring on both sides:

$0.64 = 1-\frac{v^2}{c^2}\\\\\frac{v^2}{c^2} = 1-0.64 \\v^2= 0.36c^2\\$

taking square root on both sides:

3 0

3 years ago

Please Help Meee.. Will give brainlest

anygoal [31]

Answer:

Total resistance is 19.6 Ω for the circuit .

Explanation:

Given:

Six resistors of a circuit namely $R_1$ to $R_6$ .

Where

$R_1$ and $R_2$ are in series.

$R_3$ and $R_4$ are in parallel.

$R_5$ and $R_6$ are in parallel.

We know that continuous resistor which are in series are added up to find the equivalent resistance.

Similarly resistors which are arranged in parallel their equivalent resistance is $\frac{R_3R_5}{R_3+R_5}$ for the case of $R_3$ and $R_5$ .

According to the question:

Total resistance = R(equivalent) :

⇒ $R_(eq_) = R_1+R_2+(\frac{R_3R_4}{R_3+R_4} )+(\frac{R_5R_6}{R_5+R_6} )$

⇒ $R_(eq_)=7+8+(\frac{4\times 6}{4+6} )+(\frac{3\times 8}{3+8} )$

⇒ $R_(eq_)=7+8+(\frac{24}{10} )+(\frac{24}{11} )$

⇒ $R_(eq_)=15+(2.4 )+(2.18)$

⇒ $R_(eq_)=19.58$ Ω

So the total resistance of the circuit depicted is 19.58 Ω approximated to nearest tenth that is 19.6 Ω

6 0

4 years ago

A 2.7-kg ball is thrown upward with an initial speed of 20.0 m/s from the edge of a 45.0-m-high cliff. At the instant the ball i

sveticcg [70]

Answer:

a) 72.54° and It will take the woman 33.4m

Explanation:

The woman runs with a constant speed V1 = 6m/s

V2 = 20m/s

V1 = V2 cos θ

Cos θ= V1/V2= 6/20

Cos θ= 0.3

Cos^-1 0.3=72.54°

Using Range formular for projectile

R= (V2 Cos θ)/g (V2 Sin θ)^2 +sqrt(V2 Sin θ)^2 + 2gh)

R= (20cos72.54)(2Sin72.54+sqrt(20Sin72.54)^2 + 2×9.8×45

R=33.4m

b )

see the attached file

7 0

3 years ago

f the CD rotates clockwise at 500 rpmrpm (revolutions per minute) while the last song is playing, and then spins down to zero an

vazorg [7]

Answer:

The magnitude of the angular acceleration is $a = 20.14 rad/s^2$

Explanation:

From the question we are told that

The angular speed of CD is $w_{CD} = 500 rpm = \frac{500 rpm}{\frac{60 \ s }{1 \ min} } * \frac{2 \pi }{ 1 \ rev} = 52.37 rad/s$

time taken to decelerate is $t_{CD} = 2.60\ s$

The final angular speed is $w_f= 0 \ rad/s$

The angular acceleration is mathematically represented as

$a = \frac{w_f - w_{CD}}{t}$

substituting values

$a = \frac{0 - 52.37}{2.60}$

$a = - 20.14 rad/s^2$

The negative sign show that the CD is decelerating but the magnitude is

$a = 20.14 rad/s^2$

3 0

3 years ago