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4 years ago

Why is it important for scientists to use the scientific method?

1 answer:

6 0

It is important because if they deviate then they may not achieve accurate measurable results, also so they can document their work.

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Two forces P and Q act on an object of mass 15.0 kg with Q being the larger of the two forces. When both forces are directed to

Rom4ik [11]

Answer:

P=6.25N and Q=16.25N

Explanation:

In order to solve this problem we must first draw a free body diagram for both situation, (see attached picture).

Now, we need to analyze the two free body diagrams. So let's analyze the first diagram. Since the body is accelerated, then the sum of forces is equal to mass times acceleration, so we get:

$\Sigma F=ma$

We can assume there will be only the two mentioned forces P and Q, so

the sum of forces will be:

P+Q=ma

$P+Q=(15kg)(1.50m/s^{2})$

P+Q=22.5N

We can do the same analysis for the second free body diagram:

$\Sigma F=ma$

$Q-P=(15kg)(0.7m/s^{2})$

Q-P=10.5N

so now we have a system of equations we can solve by elimination:

Q+P=22.5N

Q-P=10.5N

Now, we can add the two equations together so the P force is eliminated, so we get:

2Q=32.5N

now we can solve for Q:

$Q=\frac{32.5N}{2}$

Q=16.25N

Now we can use any of the equations to find P.

Q+P=22.5N

P=22.5N-Q

when substituting for Q we get:

P=22.5N-16.25N

P=6.25N

5 0

4 years ago

The intensity of the sound from a certain source is measured at two points along a line from the source. The points are separate

Artemon [7]

Answer:

The source is at a distance of 4.56 m from the first point.

Solution:

As per the question:

Separation distance between the points, d = 11.0 m

Sound level at the first point, L = 66.40 dB

Sound level at the second point, L'= 55.74 dB

Now,

$L = 10log_{10}\frac{I}{I_{o}}$

$I = I_{o}10^{\frac{L}{10}} = I_{o}10^{0.1L} = 10^{- 12}\times 10^{0.1\times 66.40} = 10^{- 5.36}$

$L' = 10log_{10}\frac{I'}{I_{o}}$

$I' = I_{o}10^{\frac{L'}{10}} = 10^{- 12}\times 10^{0.1\times 55.74} = 10^{- 6.426}$

where

$I_{o} = 10^{- 12} W/m^{2}$

I = Intensity of sound

Now,

$I = \frac{P}{4\pi R^{2}}$

Similarly,

$I' = \frac{P}{4\pi (R + 11.0)^{2}}$

Now,

$\frac{I}{I'} = \frac{(R + 11.0)^{2}}{R^{2}}$

$\frac{10^{- 5.36}}{10^{- 6.426}} = \frac{(R + 11.0)^{2}}{R^{2}}$

$R ^{2} + 22R + 121 = 11.64R^{2}}$

$10.64R ^{2} - 22R - 121 = 0$

Solving the above quadratic eqn, we get:

R = 4.56 m

8 0

3 years ago

How do you think gender as a social construct affects society?

Butoxors [25]

Answer:

Discrimination

Explanation:

As a society, there are people who treat men different from women. Back in time, men got paid more. Men were more likely to get a job.

4 0

3 years ago

An object at rest will stay at rest, and an object in motion will stay in

soldier1979 [14.2K]

Answer:

It is Newton's first law of motion also referred to as the law of inertia.

Explanation:

6 0

3 years ago

A solid sphere, solid cylinder, and a hollow pipe all have equal masses and radii and are of uniform density. If the three are r

scZoUnD [109]

Answer:

A ) SOLID SPHERE

Explanation:

Moment of inertia of solid sphere = 2/5 M R²

= M K² , K is called radius of gyration

K = √2/5 R

Moment of inertia of solid cylinder = 1/2 M R²

= M K² , K is called radius of gyration

K = 1 /√2 R

Moment of inertia of solid sphere = M R²

= M K² , K is called radius of gyration

K = R

For rolling on inclined plane , acceleration

a = $\frac{gsin\theta}{1+\frac{K^2}{R^2} }$

Putting the value of K for solid sphere

a for solid sphere

a = g sinθ / ( 1 +2/5)

a = .714 g sinθ

Putting the value of K for solid cylinder

a for solid cylinder

a = g sinθ / ( 1 +1/2)

a = .666 g sinθ

Putting the value of K for hollow pipe

a for hollow pipe

a = g sinθ / ( 1 +1 )

a = . 5 g sinθ

So we see that acceleration a for solid sphere is greatest and a for hollow pipe is the least. Hence solid sphere will reach the bottom earliest and hollow pipe will reach the bottom the latest.

7 0

3 years ago