Answer:
z (max) = 34500 $
x₁ = 2
x₂ = 3
Step-by-step explanation:
Hilltop College
3 hours per week preparing lessons and grading papers
Serra College
4 hours per week preparing lessons and grading papers
Total hours to spend per week preparing lessons 18
Let´s call x₁ numbers of class at Hilltop College
and x₂ numbers of class at Serra College then:
Objective function
z = 6000*x₁ + 7500*x₂
Constraints:
1.- x₁ + x₂ ≤ 5 the total number of class
2.- 3*x₁ + 4*x₂ ≤ 18
3. General constraints x₁ ≥ 0 x₂ ≥ 0 integers
After 6 iteration optimal solution is: From on-line solver
z (max) = 34500 $
x₁ = 2
x₂ = 3
X - y = 4
-y = 4 + x
y = -4 -x
x + y = 4
So, it's B
Answer: B
Step-by-step explanation:
The 15 is on the y-axis and it’s positive so it goes up
The vertex form is
where a is the coefficient, and (h,k) is the vertex. Looking at the graph, we see that the vertex is (-2,2), so h is -2 and k is 2. We see that the parabola opens upwards, so A is positive, and is stretched by a factor of 3. (We can find this by looking where the (1,1) should be. We go over 1 from the parabola, and see where the y coordinate is. This is at (-1,5), or 1 unit right and 3 units up.) Therefore, our a is 3. Plugging this into the vertex form:
Which is answer A