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Advocard [28]
3 years ago
15

Two students were doing an experiment which involved adding potassium sulfate powder to water. They added one teaspoon of potass

ium sulfate to the water and stirred it, and all the powder dissolved. They continued to do this until, after the fourth teaspoon, no more potassium sulfate would dissolve.
As more potassium sulfate dissolves in the water, the mixture becomes

a. more concentrated.
b. less concentrated.
c. dilute.
d. more cloudy.
Chemistry
1 answer:
lana [24]3 years ago
7 0

Answer:

less concentrated

Explanation:

because it will get dissociated into more ions

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Ionic compounds involve a (share, tranfer) of electrons and typically involve atoms that have (Large, similar, very different) e
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Answer:

2 Transfer; very different

Explanation:

Ionic compound are compound that are formed from transfer of electron. The cations donate the electron(s) while the anion receive the electron(s). The compound possess a positively charged end and a negatively charge end. Example of ionic compound is NaCl . The sodium donates one electron to the chlorine  to fulfill the octet rule. The sodium atom becomes positively charged  as it donate electron to the chlorine atom. The chlorine atom becomes negatively charged as it receive electron from Sodium atom.

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Which types of reactions would result in the production of gas?
mylen [45]

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Explanation:

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How are elements arranged in a periodic table
andre [41]
Periodic table is arranged according to atomic size and other properties.
6 0
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Read 2 more answers
The ka of hypochlorous acid (hclo) is 3.0 ⋅ 10−8 at 25.0 °c. calculate the ph of a 0.0375m hypochlorous acid solution.
Scrat [10]
We can set up an ICE table for the reaction:                      
                      HClO          H+     ClO-
Initial              0.0375       0        0
Change         -x               +x      +x
Equilibrium    0.0375-x     x        x

We calculate [H+] from Ka:     
     Ka = 3.0x10^-8 = [H+][ClO-]/[HClO] = (x)(x)/(0.0375-x)

Approximating that x is negligible compared to 0.0375 simplifies the equation to         
     3.0x10^-8 = (x)(x)/0.0375     
     3.0x10^-8 = x2/0.0375     
     x2 = (3.0x10^-8)(0.0375) = 1.125x10^-9     
     x = sqrt(1.125x10^-9) = 0.0000335 = 3.35x10^-5 = [H+]
in which 0.0000335 is indeed negligible compared to 0.0375.

We can now calculate pH:     
     pH = -log [H+] = - log (3.35 x 10^-5) = 4.47
6 0
3 years ago
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