Answer: after years of research if the evidence still supports a change the theory will be revised
Explanation:
I think that’s it
I think the correct answer from the choices listed above is option 3. It is the compound Silver bromide that is insoluble to water. It has a very low solubility which is approximately 0.14 milligram per liter of water. Hope this answers the question. Have a nice day.
Answer:
The NH⁺₄ and SO₄²⁻ are spectator ions.
Explanation:
Chemical equation:
NH₄OH(aq) + H₂SO₄(aq) → (NH₄)₂SO₄(aq) + H₂O(l)
Balanced Chemical equation:
2NH₄OH(aq) + H₂SO₄(aq) → (NH₄)₂SO₄(aq) + 2H₂O(l)
Ionic equation:
2NH⁺₄(aq) + 2OH⁻(aq) + 2H⁺(aq) + SO₄²⁻(aq) → 2NH⁺₄ (aq) + SO₄²⁻(aq) + 2H₂O(l)
Net ionic equation:
2OH⁻(aq) + 2H⁺(aq) → 2H₂O(l)
The NH⁺₄ and SO₄²⁻ are spectator ions that's why these are not written in net ionic equation. The water can not be splitted into ions because it is present in liquid form.
Spectator ions:
These ions are same in both side of chemical reaction. These ions are cancel out. Their presence can not effect the equilibrium of reaction that's why these ions are omitted in net ionic equation.
The Ksp refers to the equilibrium constant for a solid dissolving in an aqueous solution.
Ksp= 5.61×10⁻¹¹
The equation for this reaction is:
Mg(OH)₂ (s) ⇔ Mg²⁺ (aq) + 2 OH⁻ (aq)
And the associated equilibrium expression is:
Ksp = [Mg2+] x [OH–]²
Mg(OH)₂ its solid and because of that doesn't have molarity, so its not included.
Ksp = [Mg²⁺] x [OH–]²
5.61x10⁻¹¹ = (x) (0.200)²
x = 1,4025 x 10⁻⁹