Answer:
The mean and the standard deviation of the sampling distribution of the number of students who preferred to get out early are 0.533 and 0.82
Step-by-step explanation:
According to the given data we have the following:
Total sample of students= 150
80 students preferred to get out 10 minutes early
Therefore, the mean of the sampling distribution of the number of students who preferred to get out early is = 80/150 = 0.533
Therefore, standard deviation of the sampling distribution of the number of students who preferred to get out early= phat - p0/sqrt(p0(1-p)/)
= 0.533-0.5/sqrt(0.5*0.5/15))
= 0.816 = 0.82
80,000+4,000+300+60+7
84,367
The standard form is 84,367.
Hope this helps!
Answer:
Volume: 8x1x12=96 inches^3
Surface area: 8x1x2=16
1x12x2=24
8x12x2=192
the total surface is: 16+24+192=232 inches^2
Just move the decimal twice to the right. So 11%
I may not be correct but ok pretty sure it’s 56
