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Leona [35]
4 years ago
14

The oxidation number of hydrogen when it is in a compound other than a hydride is ____. (1 point

Chemistry
1 answer:
Lady bird [3.3K]4 years ago
3 0
The answer is +1!!!!!!!
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In a particular redox reaction, MnO2 is oxidized to MnO4– and Ag is reduced to Ag. Complete and balance the equation for this re
postnew [5]
You didn't put a + charge on one of the Ag. It has to be on the left side 

2H2O + MnO2 ==> MnO4^- + 3e + 4H^+ 

Ag^+ + e ==> Ag^+ 
Those are the two BALANCED half reactions. Multiply equation 1 by 1 and equation 2 by 3 and add them.
3 0
3 years ago
Read 2 more answers
What does the molar mass of an element represent?
IrinaK [193]

The answer is: both choices a and b.

The base SI unit for molar mass is kg/mol, but chemist more use g/mol (gram per mole).

For example, the molar mass of fluorine is 38.00 g/mol.

M(F₂) = 2 · Ar(F) · g/mol.

M(F₂) = 2 · 19.00 · g/mol.

M(F₂) = 38.00 g/mol.

Molar mass M represent the mass of a substance (in this example molecule of florine) divided by the amount of substance.

Ar is the atomic weight of a chemical element (in this example fluorine).

4 0
3 years ago
Alex dragged a log across the yard in 30 the log weighted 400n she did 900 j of work how much power did I she have
In-s [12.5K]

The power used by Alex to drag the log across the yard is determined as 2,656 W.

<h3>Mass of the log</h3>

The mass of the log is calculated as follows;

W = mg

m = W/g

m = (400)/9.8

m = 40.82 kg

<h3>Velocity of the log</h3>

K.E = ¹/₂mv²

v² = 2K.E/m

v² = (2 x 900)/(40.82)

v² = 44.096

v = 6.64 m/s

<h3>Power used by Alex</h3>

P = Fv

P = 400 x 6.64

P = 2,656 W

Learn more about power here: brainly.com/question/13881533

#SPJ1

5 0
2 years ago
Read that From picture and tell me the answer please​
Dafna11 [192]

Answer:

1g Hydrogen

Explanation:

<h3><u>Getting</u><u> </u><u>to</u><u> </u><u>the</u><u> </u><u>equation</u><u>:</u></h3>

Calcium in water reacts vigorously to give a cloudy white <em>Precipitate</em><em> </em>(compound) called Calcium hydroxide alongwith the evolution of Hydrogen gas.

\boxed{ \mathsf{Ca + H_2O \rightarrow Ca(OH)_2 + H_2}}

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

<h3><u>Balancing</u><u> </u><u>the</u><u> </u><u>equation</u><u>:</u><u> </u></h3>

This reaction is not in it's balanced form! The number of atoms of Hydrogen on the left is 2 while that on the right is 4,I.e.,they're not equal.

Adding a 2 in front of H2O solves the problem by making the number of atoms of each element on both the sides equal.

\mathsf{Ca +2 H_2O \rightarrow Ca(OH)_2 + H_2}

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

<h3><u>Observations</u><u>:</u></h3>

Looking into the equation more carefully, we see:

<u><em>1</em><em> </em></u><em>atom</em><em> </em><em>of</em><em> </em><em>Calcium</em><em> </em><em>reacts</em><em> </em><em>with</em><em> </em><em><u>2</u></em><em> </em><em>molecules</em><em> </em><em>of</em><em> </em><em>water</em><em> </em><em>to</em><em> </em><em>give</em><em> </em><u><em>1</em><em> </em></u><em>molecule</em><em> </em><em>of</em><em> </em><em>Calcium</em><em> </em><em>Hydroxide</em><em> </em><em>alongwith</em><em> </em><em><u>1</u></em><em> </em><em>molecule</em><em> </em><em>of</em><em> </em><em>Hydrogen</em><em> </em><em>gas</em><em>.</em>

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

<h3><u>Gram</u><u> </u><u>atomic</u><u> </u><u>and</u><u> </u><u>molecular</u><u> </u><u>masses</u><u> </u></h3>

<u>Mass</u><u> </u><u>of</u><u> </u><u>one</u><u> </u><u>atom</u><u> </u><u>of</u><u> </u><u>Calcium</u><u> </u>= it's gram atomic mass

= 40 g

<u>Mass of one "molecule" of Hydrogen</u>

= it's Gram molecular mass

= gram mass of one atom × number of atoms in one molecule

= 1 × 2

= 2 g

So,

according to our observation:

One atoms of Calcium gives one molecule of Hydrogen <em>(during the particular reaction)</em>

=><u> 40g of Calcium gives = 2g of Hydrogen</u>

•°• 1 g of Calcium gives = \frac{2}{40}

= \frac{1}{20} g Hydrogen

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

<h3><u>Answer</u><u>:</u></h3>

We're provided with 20g of Calcium,

=> 20g of Calcium gives = 20 × \frac{1}{20} g H2

<u>= 1 g H2</u>

_______________

Hope this helps!

6 0
3 years ago
Determine the number of hydrogen atoms in an alkyne with one carbon–carbon triple bond and 4 carbon atoms.
rewona [7]

Answer:

There are 6 hydrogen atoms.

Explanation:

The formula for an alkyne that has only one triple bond is as follows:

  • CₙH₂₍ₙ₎₋₂

Where n is any natural number greater than 2.

For this problem, n=4. This would mean the formula is:

  • C₄H₂₍₄₎₋₂

Thus

  • C₄H₈₋₂
  • C₄H₆

Thus the answer is 6, there are 6 hydrogen atoms.

4 0
3 years ago
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