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Evgesh-ka [11]
3 years ago
14

Why can you never see the far side of the mood from earth?

Chemistry
2 answers:
IRINA_888 [86]3 years ago
8 0

Its C.  because the moon rotates once on its axis in the same time that it takes to

horsena [70]3 years ago
3 0
The answer is C, because the moon does rotate it just rotates at the perfect time for us to never side the other side of it.  
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What is altered by a catalyst?
JulsSmile [24]

Answer:Effect of Catalysts on the Activation Energy. Catalysts provide a new reaction pathway in which a lower Activation energy is offered. A catalyst increases the rate of a reaction by lowering the activation energy so that more reactant molecules collide with enough energy to surmount the smaller energy barrier.

Explanation:

Your answer is in this

7 0
3 years ago
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Calculate the amount of heat required to raise the temperature of a 32g sample of water from 8°C to 22°C.
qwelly [4]

Answer:

The amount of heat required to raise the temperature of a 32g sample of water from 8°C to 22°C is 1,874.432 J

Explanation:

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

Sensible heat is the amount of heat that a body absorbs or releases without any changes in its physical state (phase change).

Between heat and temperature there is a direct proportional relationship. The constant of proportionality depends on the substance that constitutes the body and its mass, and is the product of the specific heat and the mass of the body. So, the equation that allows to calculate heat exchanges is:

Q = c * m * ΔT

where Q is the heat exchanged by a body of mass m, constituted by a substance of specific heat c and where ΔT is the variation in temperature.

In this case:

  • c= 4.184 \frac{J}{g*C}
  • m= 32 g
  • ΔT= Tfinal - Tinitial= 22°C - 8°C= 14°C

Replacing:

Q= 32 g* 4.184 \frac{J}{g*C} *14 °C

Solving:

Q= 1,874.432 J

<u><em>The amount of heat required to raise the temperature of a 32g sample of water from 8°C to 22°C is 1,874.432 J</em></u>

7 0
3 years ago
The volume of an automobile air bag was 66.8 L when inflated at 25 °C with 77.8 g of nitrogen gas. What was the pressure in the
Ray Of Light [21]

Answer:

\large \boxed{\text{103 kPa}}

Explanation:

We can use the Ideal Gas Law — pV = nRT

Data:

V = 66.8 L

m = 77.8 g

T = 25 °C

Calculations:

(a) Moles of N₂

\text{Moles of N}_{2} = \text{77.8 g N}_{2} \times \dfrac{\text{1 mol N}_{2}}{\text{28.01 g N}_{2}} = \text{2.778 mol N}_{2}

(b) Convert the temperature to kelvins

T = (25 + 273.15) K = 298.15 K

(c) Calculate the pressure

\begin{array}{rcl}pV & =& nRT\\p \times \text{66.8 L} & = & \text{2.778 mol} \times \text{8.314 kPa$\cdot$ L$\cdot$K$^{-1}$mol$^{-1}\times$ 298.15 K}\\66.8p & = & \text{6886 kPa}\\p & = & \textbf{103 kPa}\end{array}\\\text{The pressure in the bag is $\large \boxed{\textbf{103 kPa}}$}

3 0
3 years ago
Which is a type of chemical weathering?
Goshia [24]

Answer:

The correct answer is D) hydration

5 0
3 years ago
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What is the melting point of glucose?
vitfil [10]

Answer:294.80°F

Explanation:

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3 years ago
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