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3 years ago

It takes 20s for 3x10^6 electrons to flow through a wire ,what is the current?

Physics

1 answer:

Elina [12.6K]3 years ago

6 0

Answer:

Explanation:

The variables we know and are given are:

time, t = 20s

Charge, Q = 3x1-^-6 electrons, which is just 3x10^-6C (C stands for Coulombs, which is the unit for Charge)

We need to find the current, I, and since we know Q and t we can substitute these values into the given equation:

I=Q/t (which if you look at what the RHS is saying, its Charge over time, or more literally means the amount of charge passing a point over a period of time)

If we substitute these values, we will get I as:

I = Q / t

I = 3x10^-6 / 20

I = 1.5x10^-7 A

Hope this helps!

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An atom with more or less neutrons than expected is a what ?

salantis [7]

Answer:

Isotope it will have a different number of neutrons than normal

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2 years ago

1) You slam on the brakes of your car in a panic, and skid a certain distance on a straight level road. If you had been travelin

aleksandr82 [10.1K]

Answer:

d = 4 d₀o

Explanation:

We can solve this exercise using the relationship between work and the variation of kinetic energy

W = ΔK

In that case as the car stops v_f = 0

the work is

W = -fr d

we substitute

- fr d₀ = 0 - ½ m v₀²

d₀ = ½ m v₀² / fr

now they indicate that the vehicle is coming at twice the speed

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using the same expressions we find

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2 years ago

If the force on a hammer is 24 N and its mass is 1.6 kg, then the

Gnesinka [82]

Answer:

15 m/s²

Explanation:

F = ma

make "a" the subject

a = F/m

6 0

3 years ago

Imagine a simple pendulum swinging in an elevator. If the cable holding the elevator up was to snap, allowing the elevator to go

Lady_Fox [76]

One of the components that affect the period is gravity (the other is length). This gravity is basically the value of the effective acceleration that acts on the body due to gravity. When the elevator is over free fall, the effective gravity becomes zero. Mathematically this can be visualized as,

$T = 2\pi \sqrt{\frac{l}{\dot{g_{eff}}}}$

Since this value is zero, the period would tend to be infinite,

$T \rightarrow \infty$

Therefore the frequency that is inversely proportional to the period would be defined as

$f = \frac{1}{T}$

$f = \frac{1}{\infty}$

$f \approx 0$

In this way there is no frequency on the body which will not generate any oscillation on the body

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3 years ago

Someone please help? :)

Gnoma [55]

Answer:

(A) $F_N - mg\cos\theta$

Explanation:

The net force perpendicular to the surface of the incline is the sum of the gravity force component, which is mgcos(theta), and the reactionary normal force caused by the surface of the incline. The sum is F_N - mgcos(theta) and is usually 0 which is why the object is not moving perpendicularly to the surface of the incline.

8 0

3 years ago