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3 years ago

Mrs. Johnson's first test's data: 59, 22, 87, 44, 96, 38, 70, 85, 79. What is the value of Q1?

Mathematics

2 answers:

umka21 [38]3 years ago

6 0

Answer: The Answer to your question is 41

Step-by-step explanation:

I did this equasion for homework and got it wrong the answer was 41 when it was checked

matrenka [14]3 years ago

3 0

Answer:

Step-by-step explanation:

Arrange the data in an ascending order and the median is the middle value. If the number of values is an even number, the median will be the average of the two middle numbers.

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Plz help I will mark you brainlist plz help

cricket20 [7]

2- 11

3- each hour she gets 8.75

4- .80

5- 3

6 0

3 years ago

Read 2 more answers

In response to the increasing weight of airline passengers, the Federal Aviation Administration (FAA) told airlines to assume th

velikii [3]

Answer:

Because we don't know the exact shape of the population distribution since they are not Normally distributed and they are also not very non-Normal

Step-by-step explanation:

We are given;

Population standard deviation;μ = 200

Population standard deviation; σ = 35

Sample size; n = 30

We are told that the weights are not Normally distributed and they are also not very non-Normal. Therefore it means we don't know the exact shape of the population distribution and as such we can't calculate the probability that a randomly selected passenger weighs more than 200 pounds.

4 0

3 years ago

Please simplify the following distributive property expression:

guapka [62]

You are correct

4(3x-5)

4(3x) + 4(-5)

12x-20

6 0

3 years ago

Calculus 3 chapter 16

o-na [289]

Evaluate $\vec F$ at $\vec r$ :

$\vec F(x,y,z) = x\,\vec\imath + y\,\vec\jmath + xy\,\vec k \\\\ \implies \vec F(\vec r(t)) = \vec F(\cos(t), \sin(t), t) = \cos(t)\,\vec\imath + \sin(t)\,\vec\jmath + \sin(t)\cos(t)\,\vec k$

Compute the line element $d\vec r$ :

$d\vec r = \dfrac{d\vec r}{dt} dt = \left(-\sin(t)\,\vec\imath+\cos(t)\,\vec\jmath+\vec k\bigg) \, dt$

Simplifying the integrand, we have

$\vec F\cdot d\vec r = \bigg(-\cos(t)\sin(t) + \sin(t)\cos(t) + \sin(t)\cos(t)\bigg) \, dt \\ ~~~~~~~~= \sin(t)\cos(t) \, dt \\\\ ~~~~~~~~= \dfrac12 \sin(2t) \, dt$

Then the line integral evaluates to

$\displaystyle \int_C \vec F\cdot d\vec r = \int_0^\pi \frac12\sin(2t)\,dt \\\\ ~~~~~~~~ = -\frac14\cos(2t) \bigg|_{t=0}^{t=\pi} \\\\ ~~~~~~~~ = -\frac14(\cos(2\pi)-\cos(0)) = \boxed{0}$

3 0

2 years ago

I NEED SOMEONE TO PLS ANSWER THIS I WILL MARK BRAINLYEST IF U ANSWER IT CORRECTLY JUST PLEASE HELP

scoundrel [369]

1. 24
2.-40
3.-8a-8b
4. 10b+40
5. -2p-14

I believe these are right, hope this helps!!

8 0

3 years ago