The absolute minimum = -2√2.
The absolute maximum= 4.5
Consider f(t)=t√9-t on the interval (1,3].
Find the critical points: Find f'(t)=0.
f"(t) = 0
√9-t² d/dt t + t d/dt √9-t²=0
√9-t² + t/2√9-t² (-2t)=0
9-t²-t²/√9-t²=0
9-2t²=0
9=2t², t²=9/2, t=±3/√2
since -3/√2∉ (1,3].
Therefore, the critical point in the interval (1,3] is t= 3/√2.
Find the value of the function at t=1, 3/√2,3 to find the absolute maximum and minimum.
f(-1)=-1√9-1²
= -√8 , =-2√2
f(3/√2)= 3/√2 √9-(3/√2)²
= 3/√2 √9-9/2
=3/√2 √9/2
=9/2 = 4.5
f(3)= 3√9-3²
= 3(0)
=0
The absolute maximum is 4.5 and the absolute minimum is -2√2.
The absolute maximum point is the point at which the function reaches the maximum possible value. Similarly, the absolute minimum point is the point at which the function takes the smallest possible value.
A relative maximum or minimum occurs at an inflection point on the curve. The absolute minimum and maximum values are the corresponding values over the full range of the function. That is, the absolute minimum and maximum values are bounded by the function's domain.
Learn more about Absolute minimum and maximum here:brainly.com/question/19921479
#SPJ4
Answer:
Any number really are there any pacific numbers
Step-by-step explanation:
The name of the arc formed by the central angle ∠GQJ is (c) GJ
<h3>How to name the arc?</h3>
The central angle is given as:
∠GQJ
The above means that the center of the circle is located at point Q.
When the point Q is removed from the name of the central angle, we have points G and J
These represent the endpoints of the arc.
Hence, the name of the arc formed by the central angle ∠GQJ is (c) GJ
Read more about arcs at:
brainly.com/question/2005046
#SPJ1
