Answer:
The answer is AlCl3
Explanation:
Aluminum chloride is a salt made of aluminum and chlorine. It is presented as a yellow powder thanks to impurities due to the presence of iron chloride. AlCl3 is flat trigonal, and it is not polar. Their dipole moment of each Al-Cl links have angles of 120 degrees to each other and, therefore, are canceled. This is why this molecule is nonpolar.
The concentration of the HBr would be 0.09 M
<h3>What are stoichiometric problems?</h3>
First, let us look at the equation of the reaction:
The mole ratio of HBr to NaOH is 1:1.
Mole of 15 mL, 0.30 M NaOH = 0.30 x 15/1000 = 0.0045 moles
Equivalent mole of HBr - 0.0045 moles
Molarity of HBr = mole/volume = 0.0045/50/1000 = 0.09 M
More on stoichiometric problems can be found here: brainly.com/question/15047541
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The given question is incomplete. The complete question is:
A chemist adds 0.85 L of a 0.0050M calcium sulfate to a reaction flask. Calculate the mass in grams of calcium sulfate the chemist has added to the flask. Round your answer to significant digits.
Answer: The mass in grams of calcium sulfate the chemist has added to the flask is 0.58 g
Explanation:
Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.
where,
n = moles of solute
= volume of solution in L
moles of =
Now put all the given values in the formula of molarity, we get
Therefore, the mass in grams of calcium sulfate the chemist has added to the flask is 0.58 g
Answer:
it is 92
Explanation:
Atomic Mass 238.029 atomic mass units
Number of Protons 92
Number of Neutrons 146
Number of Electrons 92
Answer:
5.65mg of the isotope remains
Explanation:
The radioactive decay follows the equation:
Ln[A] = -kt + ln[A]₀
<em>Where [A] is amount of the isotope after time t, k is decay constant, and [A]₀ is initial amount of the isotope.</em>
k = ln 2 / Half-life
k = ln 2 / 3.82 days
k = 0.18145days⁻¹
Replacing:
Ln[A] = -0.18145days⁻¹*10.1days + ln[35.3mg]
ln[A] = 1.7312
[A] = 5.65mg of the isotope remains
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