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Likurg_2 [28]
3 years ago
14

Which of the following molecules is nonpolar? CO, NO, ALCL3, SO2

Chemistry
1 answer:
tekilochka [14]3 years ago
7 0

Answer:

The answer is AlCl3

Explanation:

Aluminum chloride is a salt made of aluminum and chlorine. It is presented as a yellow powder thanks to impurities due to the presence of iron chloride. AlCl3 is flat trigonal, and it is not polar. Their dipole moment of each Al-Cl links have angles of 120 degrees to each other and, therefore, are canceled. This is why this molecule is nonpolar.

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A compound A has prominent infrared absorptions at 1050, 1786, and 1852 cm–1 and shows a single absorption in the proton NMR spe
olya-2409 [2.1K]

Answer:

Compound A is succinic anhydride and B is methyl succinate (the monomethyl ester).

Structural Diagram is attached.

Explanation:

A.

Succinic anhydride appears as colorless needles or white crystalline solid. ... Succinic anhydride, also called dihydro-2, 5-furandione, is an organic compound with the molecular formula C4H4O3. It is the acid anhydride of succinic acid.

B.

Monomethyl succinate is a dicarboxylic acid monoester that is succinic acid in which one of the carboxy groups has been converted to its methyl ester. It is a dicarboxylic acid monoester and a hemisuccinate. ... They have the general structure RC(=O)OR', where R=fatty aliphatic tail or organyl group and R'=methyl group.

4 0
3 years ago
XTRA POINTS 4 CHRISTMAS <br> What is an empirical formula?
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Explanation:

a formula giving the proportions of the elements present in a compound but not the actual numbers or arrangement of atoms.

6 0
2 years ago
Read 2 more answers
Write A balanced equation showing the formation of copper (II) nitrite from its elements
34kurt

Answer:

Cu(s) + N₂(g) + 2O₂(g) ⟶ Cu(NO₂)₂(s)

4 0
3 years ago
Elements that readily lose electrons tend to have
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Explanation:

8 0
3 years ago
A chemical reaction requires 31.39 kJ. How many kilocalories does this correspond to?
Allushta [10]
<h3>Answer:</h3>

7.502 kilo calories

<h3>Explanation:</h3>

<u>We are given;</u>

  • Quantity of heat, Q as 31.39 kJ

We are required to convert it to kilo calories

First, we convert it to Joules

1 kJ = 1000 J

Therefore;

31.39 kJ will be equivalent to 31390 Joules

Second we convert Joules to calories using a suitable conversion factor

The suitable conversion factor is 4.184 J/Cal

Thus;

31390 Joules will be equivalent to;

= 31390 J ÷ 4.184 J/Cal

= 7502.39 Cal

Third, we convert calories to kilo calories

1 kCal = 1000 cal

Therefore;

7502. 39 Cal will be equivalent to;

= 7502.39 ÷ 1000

= 7.50239

=7.502 kilo calories

Hence, 31.39 kJ will correspond to 7.502 kilo calories

3 0
3 years ago
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