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snow_tiger [21]
4 years ago
12

When 3.77 moles of sodium carbonate react with excess calcium phosphate, how many moles of product will be produced from this re

action?

Chemistry
1 answer:
elixir [45]4 years ago
3 0

The solution is included.

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Answer:

13.93\ \text{g}

Explanation:

Molecular weight of CaCO_3 = 100.0869 g/mol

Mass of CaCO_3 = 31.7 g

Moles of CaCO_3 = \dfrac{31.7}{100.0869}=0.3167\ \text{mol}

Moles of both CaO and CO_2 is 0.3167\ \text{mol}

Molecular weight of CO_2 = 44 g/mol

Mass of CO_2 = 44\times 0.3167=13.93\ \text{g}

The mass of carbon dioxide formed simultaneously is 13.93\ \text{g}.

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bonds within the nucleus of reactants atoms are broken and rearranged to form new product atoms

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